This has probably been asked 100 times, but I couldn't find any articles on point. I have a script that runs on the last day of every month at 11:30pm. If cats a number of input tables that were created the previous month (or earlier), combines them into one master file and erases the indivual... (1 Reply)
Hi, I'm new with Unix, I'm trying to get a last day of previous month with this format: %b %d %Y (example: Feb 25 2008).
Here is what I have so far.
#!/bin/ksh
cur_month=`date +%m`
cur_year=`date +%Y`
prev_month=$(($cur_month-1))
# Check to see if this is January
if
then
... (11 Replies)
Hello,
I'm new to shell scripting.
We've develop a script which will grep a file on the search criteria, MON (Jan/Feb/Mar/etc). But we should set this sript in cron which will run on every first day of the month. The problem I'm having is, when I run the script, it is displaying the contents of... (7 Replies)
Can someone help me creating a function which will give me previous months.
like for example if the date is 200902 and if i call my function and pass a parameter 2 i want to get 200812 as the answer.
or if i pass 200902 with a parameter 7 then my function should give me the date as 200807. (1 Reply)
Hi,
On any given day, I want to capture the month that has gone by - said otherwise, how do I capture last month?
expr date '+%m' - 1
Above expression is giving error.
Please advise
thanks
---------- Post updated at 09:28 AM ---------- Previous update was at 09:11 AM... (1 Reply)
Hi All,
I am using the below code to get the year and month from date:
Below gives output like 201212.
dt=`date '+%Y%m'`
how do i get the previous month value(ie: subtract 1 from date)
example output:
dt=201211
Please help. :confused: (3 Replies)
I have requirment to get last date of previous month and the first date of previous 4th month:
Example:
Current date: 20130320 (yyyymmdd)
Last date of previous month: 20130228 (yyyymmdd)
First date of previous 4th month: 20121101 (yyyymmdd)
In my shell --date, -d, -v switches are not... (3 Replies)
could you please assist the below query.
i had written the below piece of code to copy the files from one directory to another. For current month files had been copied ,unfortunately the previous month files not copied.
Please find the below directory structure:-
ls -lrt
total 1824... (2 Replies)
Discussion started by: venkat918
2 Replies
LEARN ABOUT REDHAT
cal
CAL(1) BSD General Commands Manual CAL(1)NAME
cal -- displays a calendar
SYNOPSIS
cal [-smjy13] [[month] year]
DESCRIPTION
Cal displays a simple calendar. If arguments are not specified, the current month is displayed. The options are as follows:
-1 Display single month output. (This is the default.)
-3 Display prev/current/next month output.
-s Display Sunday as the first day of the week. (This is the default.)
-m Display Monday as the first day of the week.
-j Display Julian dates (days one-based, numbered from January 1).
-y Display a calendar for the current year.
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calen-
dar for 1989. Two parameters denote the month (1 - 12) and year. If no parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's.) Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
OTHER VERSIONS
Several much more elaborate versions of this program exist, with support for colors, holidays, birthdays, reminders and appointments, etc.
For example, try the cal from http://home.sprynet.com/~cbagwell/projects.html or GNU gcal.
BSD June 6, 1993 BSD