I need to find files that have the ending of .out and that are older than 20 days. However, I cannot use find as I do not want to search in the directories that are underneath the directory that I am searching in.
How can this be done?? Find returns files that I do not want. (2 Replies)
Yes , I have to find a file in unix without using any find or where commands.Any pointers for the same would be very helpful as i am beginner in shell scritping and need a solution for the same.
Thanks in advance.
Regards
Jatin Jain (10 Replies)
Given two files of the same format (For example number1|text1|number2) what is the command to print lines in file1 which do not occur in file2? diff command seems a bit complicated for me for this purpose. Please help!! Thank you very much. (3 Replies)
Hi all,
I have difficulty to solve the followign problem.
mydata:
StartPoint EndPoint
22 55
2222 2230
33 66
44 58
222 240
11 25
22 60
33 45
The union of above... (2 Replies)
Hi,
A piece of script from Perl-cookbook I do not understand, and post here for explanation.
The purpose is to find the element in either array (union), and in both array (intersection). Thank you in advance.
@a=qw(1 3 5 6 7 8);
@b=qw(2 3 5 7 9);
foreach $e (@a, @b) {$union{$e}++ &&... (3 Replies)
My concept may sound a bit cryptic but I what some startup information as to how we can use GDB APIs / debugging techniques in programs with GCC when we compile the program. We can definitely tell gcc to link GDB libs also. The ultimate aid would be that when the compiled programs executes it... (4 Replies)
Sorry for the “word salad” subject, but I wanted to cast a wide net for help.
I've created an IP (Internet Protocol) server which serves HTTP, SMTP, and FTP requests.
As you probably know, they all require creating a socket, listening on it, accepting connections, and then having a short... (3 Replies)
I need to find a word '% Retail by State' in the folder /usr/sas/reports/RetailSalesTaxallocation.
When I tried like below,
-bash-4.1$ cd /usr/sas/reports/RetailSalesTaxallocation
-bash-4.1$ find ./ -name % Retail by State
find: paths must precede expression: Retail
Usage: find ... (10 Replies)
Discussion started by: Ram Kumar_BE
10 Replies
LEARN ABOUT DEBIAN
mp3cut
MP3CUT(1) User Command MP3CUT(1)NAME
mp3cut - cut and assemble MP3 files
SYNOPSIS
mp3cut [ -o outputfile ] [ -T title ] [ -A artist ] [ -N album-name ] [ -t [hh:]mm:ss[+ms]-[hh:]mm:ss[+ms] ] mp3file [[ -t ... ] mp3file1
...]
DESCRIPTION
The mp3cut utility cuts and assembles MP3 files according to the time specifications given on the command line. The mp3 output is written
to the outputfile. If no outputfile is given on the command-line, the name for the outputfile is created from the name of the first mp3
file by adding output.mp3 at the end. The -t flag specifies which part of the mp3 file following it will be extracted.
OPTIONS -o outputfile
Specify where the output is to be written.
-T title
Specify the title ID3 tag for the output file.
-A artist
Specify the artist ID3 tag for the output file.
-N album-name
Specify the album name ID3 tag for the output file.
-t [hh:]mm:ss[+ms]-[hh:]mm:ss[+ms]
Specify which part of the following mp3file will be included in the output file.
hh = hours
mm = minutes
ss = seconds
ms = milliseconds
If the starting time is omitted, 00:00:00+00 is used as starting time. If the ending time is omitted, the end of the MP3 file is
used as ending time.
EXAMPLES
mp3cut -o output.mp3 -t 23:42+500-01:23:42+750 input.mp3
Cut the segment from 23 minutes, 42 seconds and 500 milliseconds to 1 hour, 23 minutes, 42 seconds and 750 milliseconds from
input.mp3 and write the output to output.mp3.
mp3cut -t 00:01-00:02 input1.mp3 -t -15:23 input2.mp3 -t 9:87+500- input3.mp3
Append the segments from input1.mp3, input2.mp3 and input3.mp3 and write the output to input1.output.mp3.
AUTHORS
Manuel Odendahl <manuel@bl0rg.net>, Florian Wesch <dividuum@bl0rg.net>
February 2005 MP3CUT(1)