10-22-2001
try this...
I assume you are trying to grab the output of the list command.
If so, try using "awk"...
ls -l file |awk '{print $6 $7 }'
this will list only the 2 date columns from the modified date. (the 6 and 7 are column number from the -l . adjust it where you may need to )
Output this to a file, and you can convert it from there.
The date will look like this :
Oct19
(sorry no spaces)
For better use of the "awk" command see the man page.
RECON
10 More Discussions You Might Find Interesting
1. Solaris
Hi
In unix i want to zip the files in a directory excluding *.dmp, *.log, *.lst, *.out files in that directory. pls let me know what command to use.
$zip ........ ?
Thanks (1 Reply)
Discussion started by: dreams5617
1 Replies
2. UNIX for Dummies Questions & Answers
Hello,
I am trying to return the name of the resulting file from a .zip archive file using unix unzip command.
unzip c07212007.cef7081.zip
Archive: c07212007.cef7081.zip
SecureZIP for z/OS by PKWARE
inflating: CEP/CEM7080/PPVBILL/PASS/G0063V00
I used the following command to unzip in... (5 Replies)
Discussion started by: oracledev
5 Replies
3. Shell Programming and Scripting
if you have a file that is zipped and has various files within can you add a file to this at all?
i.e. ZIP folder called logs.zip - contains files zip1, zip2, zip3
need to add build.zip (contains file zip4) to logs.zip so logs.zip will now look like this - zip1.zip2.zip3,zip4?
can this be... (2 Replies)
Discussion started by: Pablo_beezo
2 Replies
4. UNIX for Dummies Questions & Answers
Hi guys,
I have a question about the zip command. Right now I have a directory with some files and folders on it that I want to compress. When I run the zip command:
zip foo -r
I am getting a foo.zip file that once I unzip it contains a foo folder. I want to create the foo.zip, but that... (1 Reply)
Discussion started by: elioncho
1 Replies
5. AIX
I have to zip many pdf files and the size of zip file must not exceed 200 MB. When size is more than 200 MB then multiple zip files needs to be created.
How we can achieve this in UNIX?
I have tried ZIP utility but it takes a lot of time when we add individual pdfs by looping through a... (1 Reply)
Discussion started by: tom007
1 Replies
6. UNIX for Dummies Questions & Answers
Hi,
I need to zip a .dat file with .zip extension. I tried using the "zip" command. But shell says. "ksh: zip: not found"
Currently I am using gunzip to zip and changing the extension ".gz" to ".zip" as follows.
mv $file `echo $file | sed 's/\(.*\.\)gz/\1zip/'`
But when I tried... (1 Reply)
Discussion started by: aeroticman
1 Replies
7. UNIX for Advanced & Expert Users
I've a zip file called Z00.zip and in that file there are 22 more zip files. Each zip file having .txt files nearly 10,000 files. I am trying to unzip all these .txt files in one command line to unzip each .zip file from Z00.zip file. Would like to know whether possible to unzip all sub-zip files... (1 Reply)
Discussion started by: nvkuriseti
1 Replies
8. Shell Programming and Scripting
Hi
I have a requirement in unix shell where I need to zip multiple files on server to one single .zip file. I dont see zip command in AIX and gzip command not doing completely what I want.
One I do .zip file, I should be able to unzip in my local Computer.
Here is example what I want... (9 Replies)
Discussion started by: RAMA PULI
9 Replies
9. UNIX for Beginners Questions & Answers
Hi all i am very new to shell scripting and need some help from you to learn
1)i have some log files that gets generated on daily basis example: i have abc_2017_01_30_1.log ,2017_01_30_2.log like wise so i want to zip this 4 logs which are created on same date into one zip folder.
2)Post zipping... (2 Replies)
Discussion started by: b.saipriyanka
2 Replies
10. Shell Programming and Scripting
Hi all i am very new to shell scripting and need some help from you to learn
1)i have some log files that gets generated on daily basis example: i have abc_2017_01_30_1.log ,2017_01_30_2.log like wise so i want to zip this 4 logs which are created on same date into one zip folder.
2)Post zipping... (1 Reply)
Discussion started by: b.saipriyanka
1 Replies
LEARN ABOUT CENTOS
dm_date
DM_DATE(1) User Contributed Perl Documentation DM_DATE(1)
NAME
dm_date - print out the system date and time
SYNOPSIS
This performs the same operation as the unix 'date' command, but using the Date::Manip module.
dm_date [OPTION]... [+FORMAT]
DESCRIPTION
This displays information about the current system time, or some other time. Options are:
-h, --help
Print online help.
-d STRING, --date=STRING
Display time described by STRING. STRING can be any string which can be parsed by Date::Manip. Please refer to the Date::Manip::Date
documentation for details.
-f DATEFILE, --file=DATEFILE
This reads each line in DATEFILE, and extracts a date from it and prints out the information.
Blank lines and lines starting with a pound (#) are ignored. Lines not containing a valid date are also ignored.
-r FILE, --reference=FILE
Displays the last modification time of FILE.
-R, --rfc-2822
Displayc the date and time in RFC 2822 format.
Example: Mon, 07 Aug 2006 12:34:56 -0600
-u, --utc, --universal
Converts the date to UT (GMT) and prints out the information.
Only one of -d, -f, or -r should be included. If more than one is included, the first one from the list (-d, -f, -r) is used and any other
is ignored.
The format string starts with a plus (+) and contains any of the format directives described in Date::Manip::Date.
KNOWN BUGS
None known.
BUGS AND QUESTIONS
Please refer to the Date::Manip::Problems documentation for information on submitting bug reports or questions to the author.
SEE ALSO
Date::Manip::Date
LICENSE
This script is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
AUTHOR
Sullivan Beck (sbeck@cpan.org)
perl v5.16.3 2014-06-09 DM_DATE(1)