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Top Forums UNIX for Advanced & Expert Users Changing default permissions -without "umask"-... Post 89984 by dangral on Thursday 17th of November 2005 10:08:51 AM
Old 11-17-2005
Quote:
Originally Posted by chicoGuapo
Ok, I understand this. I understand what is "umask" used for.

But i am not convinced about that.

I am sure these numbers (666 and 777) have to be defined anywhere. Where?

Maybe I am wrong, it is possible. But if not, i want to know the answer.

Again, thanks for your time.
umask does not modify permissions on any existing file. It only affects the permissions on newly created files. In your shell prompt, type umask, which shows the current setting. There's more about umask here
Code:
user@machine[/home/user]>umask
022

 

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UMASK(3)								 1								  UMASK(3)

umask - Changes the current umask

SYNOPSIS
int umask ([int $mask]) DESCRIPTION
umask(3) sets PHP's umask to $mask & 0777 and returns the old umask. When PHP is being used as a server module, the umask is restored when each request is finished. PARAMETERS
o $mask - The new umask. RETURN VALUES
umask(3) without arguments simply returns the current umask otherwise the old umask is returned. EXAMPLES
Example #1 umask(3) example <?php $old = umask(0); chmod("/path/some_dir/some_file.txt", 0755); umask($old); // Checking if ($old != umask()) { die('An error occurred while changing back the umask'); } ?> NOTES
Note Avoid using this function in multithreaded webservers. It is better to change the file permissions with chmod(3) after creating the file. Using umask(3) can lead to unexpected behavior of concurrently running scripts and the webserver itself because they all use the same umask. PHP Documentation Group UMASK(3)
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