Sponsored Content
Top Forums Shell Programming and Scripting Find and replace the value in a variable Post 83915 by Ygor on Tuesday 20th of September 2005 09:28:46 PM
Old 09-20-2005
I=${I%ssh-dummy-shell}true
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

find and replace text with a variable?

Is there a way that I can make the following work with using variables? perl -pi -e 's#blah#hrm#ig' replacetext but like this var=blah perl -pi -e 's#$var#hrm#ig' replacetext (3 Replies)
Discussion started by: doublejz
3 Replies

2. Shell Programming and Scripting

Replace variable with a user defined variable

I have a file that has a list of entries in a column x z z z x y z The column can have any length and any number of any strings. I need to replace each unique string with a user defined number. I can filter the unique entries out using awk '{if (NF==5) print $2}' file | uniq | nl >... (1 Reply)
Discussion started by: ce124
1 Replies

3. Shell Programming and Scripting

find and replace variable

Is there an easy way of doing this cat file1 jkasjhjgfg LTRIM(RTRIM(aa_bb_cde)) aragsfdg LTRIM(RTRIM(aa_bb_cde)) aregfafdgfg sdgsfdagdfg gadfg eafgsadgsa asdgsfdgag LTRIM(RTRIM(aa_bb_cde)) rfghsdfhd I want to replace each occurence of LTRIM(RTRIM($x)) with LENGTH(LTRIM(RTRIM($x)))=0... (4 Replies)
Discussion started by: alfredo123
4 Replies

4. Shell Programming and Scripting

How to replace variable inside the variable

hi sir, i need your help for this script inside /rnmucdr/ednms05/ken/xMNBDF045_Script.sql content variable like this select * from invoice where bill_date=$BILLDATE and startNum=$STARTPARTNNUM and total_partn=$TOTALPARTN if i just paste this replace with the $SCRIPT it works great,if... (31 Replies)
Discussion started by: mani_um
31 Replies

5. Shell Programming and Scripting

How to partially replace variable value?

I have variable $2 whose value is expdp_SDW_MSTR_VMDB.par I want to replace three characters from right (par) with (log) Input --> expdp_SDW_MSTR_VMDB.par Output --> expdp_SDW_MSTR_VMDB.log Thanks Deep (2 Replies)
Discussion started by: deep.singh
2 Replies

6. Shell Programming and Scripting

Find and replace with variable using sed or awk

hi, i have file say email.temp looks like Bell_BB 17 Bell_MONTHLY 888 SOLO_UNBEATABLE 721 and another file r3 Bell BB,Bell_BB Bell,Bell_MONTHLY SOLO,SOLO_UNBEATABLE i want email.temp files $1 say Bell_BB should be replaced by r3 Bell BB and Bell_MONTHLY by... (2 Replies)
Discussion started by: raghavendra.cse
2 Replies

7. Shell Programming and Scripting

Find and replace string from file which contains variable and path - SH

e.g. /home/$USER/.config replace it with "" (empty) Is this possible? I think you should play a bit with sharps ## and sed:b: (2 Replies)
Discussion started by: hakermania
2 Replies

8. Shell Programming and Scripting

Find a variable in a file and replace its value

HI , I can't find a solution to the following: In a simple menu script I want to capture the input from the user with "read" and use it as a value in a variable Rempages="some_value" which is in a different script file. So I have to perform a search and replace for this variable and only... (4 Replies)
Discussion started by: svetoslav_sj
4 Replies

9. Red Hat

How to pass value of pwd as variable in SED to replace variable in a script file

Hi all, Hereby wish to have your advise for below: Main concept is I intend to get current directory of my script file. This script file will be copied to /etc/init.d. A string in this copy will be replaced with current directory value. Below is original script file: ... (6 Replies)
Discussion started by: cielle
6 Replies

10. Shell Programming and Scripting

find and replace with variable -sed

Hi, I have a ksh script where I am trying to mask the password in the log files. $loc - is my directory $PGUIDE_DB_USER_PSW - is a variable that holds the password I am looking for find $loc/logs -type f -exec sed -i "s/$PGUIDE_DB_USER_PSW/*****/"g {} \; I get an error: ... (2 Replies)
Discussion started by: amitlib
2 Replies
GIT-SHELL(1)                                                        Git Manual                                                        GIT-SHELL(1)

NAME
git-shell - Restricted login shell for Git-only SSH access SYNOPSIS
chsh -s $(command -v git-shell) <user> git clone <user>@localhost:/path/to/repo.git ssh <user>@localhost DESCRIPTION
This is a login shell for SSH accounts to provide restricted Git access. It permits execution only of server-side Git commands implementing the pull/push functionality, plus custom commands present in a subdirectory named git-shell-commands in the user's home directory. COMMANDS
git shell accepts the following commands after the -c option: git receive-pack <argument>, git upload-pack <argument>, git upload-archive <argument> Call the corresponding server-side command to support the client's git push, git fetch, or git archive --remote request. cvs server Imitate a CVS server. See git-cvsserver(1). If a ~/git-shell-commands directory is present, git shell will also handle other, custom commands by running "git-shell-commands/<command> <arguments>" from the user's home directory. INTERACTIVE USE
By default, the commands above can be executed only with the -c option; the shell is not interactive. If a ~/git-shell-commands directory is present, git shell can also be run interactively (with no arguments). If a help command is present in the git-shell-commands directory, it is run to provide the user with an overview of allowed actions. Then a "git> " prompt is presented at which one can enter any of the commands from the git-shell-commands directory, or exit to close the connection. Generally this mode is used as an administrative interface to allow users to list repositories they have access to, create, delete, or rename repositories, or change repository descriptions and permissions. If a no-interactive-login command exists, then it is run and the interactive shell is aborted. EXAMPLE
To disable interactive logins, displaying a greeting instead: $ chsh -s /usr/bin/git-shell $ mkdir $HOME/git-shell-commands $ cat >$HOME/git-shell-commands/no-interactive-login <<EOF #!/bin/sh printf '%s ' "Hi $USER! You've successfully authenticated, but I do not" printf '%s ' "provide interactive shell access." exit 128 EOF $ chmod +x $HOME/git-shell-commands/no-interactive-login To enable git-cvsserver access (which should generally have the no-interactive-login example above as a prerequisite, as creating the git-shell-commands directory allows interactive logins): $ cat >$HOME/git-shell-commands/cvs <<EOF if ! test $# = 1 && test "$1" = "server" then echo >&2 "git-cvsserver only handles "server"" exit 1 fi exec git cvsserver server EOF $ chmod +x $HOME/git-shell-commands/cvs SEE ALSO
ssh(1), git-daemon(1), contrib/git-shell-commands/README GIT
Part of the git(1) suite Git 2.17.1 10/05/2018 GIT-SHELL(1)
All times are GMT -4. The time now is 06:59 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy