You're right, molonede, "0 0 1-7 * 1 somecommand" will run command on the first 7 days of each month and on every Monday of each month. We all wish it worked the way punter5, but it doesn't. This means that you can't get what you via crontab alone.
This usual solution is something like, first write a wrapper script that will run somecommand only if the day of the month is 7 or less:
Code:
#! /usr/bin/ksh
day=$(date +%d)
if ((day <= 7)) ; then
exec somecommand
fi
exit 1
Then run the wrapper every Monday: "0 0 * * 1 wrapper".
Morning everyone.
You'll need to excuse me for I'm running a little empty this morning.
Need to execute a job every second Tuesday of the month. Am I correct in my understanding that this isn't possible directly from crontab & hence I'll need to script. Does anyone have any similar solutions ?... (2 Replies)
Instead of the first five fields, one of eight special strings may appear:
string meaning
------ -------
@reboot Run once, at startup.
@yearly Run once a year, "0 0 1 1 *".
@annually (same as @yearly)
@monthly Run once a month, "0 0 1 * *".
@weekly Run once... (2 Replies)
I know I can't schedule this in cron and would have to write a wrapper around my script and schedule it in cron ....but not sure how do to this?
How do I exclude Monday if the 2nd day of the month falls on a Monday?
Thanks.
I tried this:
0 0 2 * 0,2-6 command
And I know this doesnt... (2 Replies)
Hello,
I wanted to set Crontab for 4th and 25th of every month at 5:00 PM.
Script should take previous month and current year as command line arguement like...
/home/test1.sh -f ABCD 03 2014
so above script will run on 4th and 25th April 2014 but argument should be like previous month... (11 Replies)
Hi,
I have came across the scenario where, we have to run the script on second and fourth Monday of each month.
I have tried to search man page of date and also forum for it but, could not get any answer to this.
Can you please advise how can we get second and fourth Monday of the month?
... (18 Replies)
Discussion started by: Prathmesh
18 Replies
LEARN ABOUT PLAN9
cron
CRON(8) System Manager's Manual CRON(8)NAME
cron - clock daemon
SYNOPSIS
auth/cron [-c]
DESCRIPTION
Cron executes commands at specified dates and times according to instructions in the files /cron/user/cron. It runs only on an authentica-
tion server. Option -c causes cron to create /cron/user and /cron/user/cron for the current user; it can be run from any Plan 9 machine.
Blank lines and lines beginning with # in these files are ignored. Entries are lines with fields
minute hour day month weekday host command
Command is a string, which may contain spaces, that is passed to an rc(1) running on host for execution. The first five fields are integer
patterns for
minute 0-59
hour 0-23
day of month 1-31
month of year 1-12
day of week 0-6; 0=Sunday
The syntax for these patterns is
time : '*'
| range
range : number
| number '-' number
| range ',' range
Each number must be in the appropriate range. Hyphens specify inclusive ranges of valid times; commas specify lists of valid time ranges.
To run the job, cron calls host and authenticates remote execution, equivalent to running rx host command (see con(1)). The user's profile
is run with $service set to rx.
Cron is not a reliable service. It skips commands if it cannot reach host within two minutes, or if the cron daemon is not running at the
appropriate time.
EXAMPLES
Here is the job that mails system news.
% cat /cron/upas/cron
# send system news
15 8-17, 21 *** helix /mail/lib/mailnews
%
SOURCE
/sys/src/cmd/auth/cron.c
SEE ALSO con(1), rc(1)CRON(8)