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Full Discussion: a find script
Top Forums Shell Programming and Scripting a find script Post 81387 by blowtorch on Friday 19th of August 2005 02:30:12 AM
Old 08-19-2005
a find script
I wrote this find script for all those questions about 'files created in the last three hours' and 'files created more than 2 minutes ago'. This script *will* recurse into subdirectories.
As always, please suggest/make changes as you see fit.

Code:
#!/usr/bin/ksh
#set -x                 # unhash for debugging

print_help(){
        echo "Usage: find.sh <num><h|m> dir_to_search_in <older|newer>"
        echo "example:
        find.sh 3m /tmp newer
this will search in /tmp for files created in the last 3 minutes.
        find.sh 3h /tmp older
this will search in /tmp for files older than 3 hours."
}

PERLDIR=/opt/perl/bin # you can specify the path of your perl binary here
if [ $# -ne 3 ]; then
        print_help
        exit -2
fi
ARG1=$1
ARG2=$2
ARG3=$3

case "$ARG3" in
        "newer") new_val="-newer";;
        "older") new_val="! -newer";;
        *) print_help; exit -2;;
esac
unit=`$PERLDIR/perl -w -e 'print chop $ARGV[0]' $ARG1`
diff=`$PERLDIR/perl -w -e 'print substr $ARGV[0],0,-1' $ARG1`
case $unit in
        h) mult=3600;;
        m) mult=60;;
        *) print_help; echo "PLEASE NOTE: Only hour or minute granularity supported. For coarser stuff, use regular find. Finer granularity not yet supported."; exit -1;;
esac
diff_sec=$(($diff*$mult))
then_time=`$PERLDIR/perl -w -e '@mytime=localtime (time - $ARGV[0]); printf "%d%.2d%.2d%.2d%.2d", $mytime[5]+1900,$mytime[4]+1,$mytime[3],$mytime[2],$mytime[1];
' $diff_sec`

touch -m ${then_time} $ARG2/file_for_find
find $ARG2 -type f $new_val $ARG2/file_for_find
rm $ARG2/file_for_find
exit

--EDIT--
This has been tested on a HPUX 11.11 system. All utilities are HPUX standard.
--EDIT--
Last edited by blowtorch; 08-19-2005 at 03:46 AM..
 

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LEARN ABOUT OSF1

uudemon

uudemon(4)						     Kernel Interfaces Manual							uudemon(4)

NAME

       uudemon.admin,  uudemon.cleanu,	uudemon.hour,  uudemon.poll  -	Administrative shell scripts for polling remote systems, cleaning up spool
       directories, reporting status to the system administrator, and routine invocations of the uuxqt and uusched daemons

SYNOPSIS

       These shell scripts reside in the following directory:
	  /usr/lib/uucp

DESCRIPTION

       All the scripts can be run from the command line or can be run automatically by the cron daemon. To automatically run the  scripts,  remove
       the comment character (#) from the beginning of the relevant line in the /var/spool/cron/crontabs/uucp file.

       This  script  reports  status  to  the system administrator. It issues the uustat command to find out the status of uucp jobs. It mails the
       results to the uucp login ID. The script may be modified to send mail to any login ID such as the uucp administrative login ID  (uucpa)	or
       root.  This script cleans up the /var/spool/uucp and /var/spool/uucppublic directories by running the uucleanup command. The uucleanup com-
       mand is run with the following parameters: -C7, -D7, X2, -o2, -W1.  This script runs the uusched and uuxqt daemons in the background.  This
       script  polls  the  systems  listed  in	the  /usr/lib/uucp/Poll file.  The uudemon.poll script should be scheduled before the uudemon.hour
       script. This allows uudemon.poll to create any command files before cron runs the uudemon.hour script.

FILES

       Contains the uudemon.admin, uudemon.cleanu, uudemon.hour and uudemon.poll files.  Contains the uucp file.

RELATED INFORMATION

       Commands: cron(8), uucleanup(8), uusched(8), uuxqt(1)

       Files: /usr/lib/uucp delim off

																	uudemon(4)
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