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Full Discussion: improve this?
Top Forums Shell Programming and Scripting improve this? Post 80064 by blowtorch on Wednesday 3rd of August 2005 01:40:14 AM
Old 08-03-2005
improve this?

Wrote this script to find the date x days before or after today. Is there any way that this script can be speeded up or otherwise improved?
Code:
#!/usr/bin/sh

check_done() {
        if [ $month -eq 1 -o $month -eq 3 -o $month -eq 5 -o $month -eq 7 -o $month -eq 8 -o $month -eq 10 -o $month -eq 12 ]
        then
                daysofmth=31
        elif [ $month -eq 2 ]
        then
                if [ `expr $year % 100` -eq 0 -a `expr $year % 400` -eq 0 ]
                then
                        daysofmth=29
                elif [ `expr $year % 100` -ne 0 -a `expr $year % 4` -eq 0 ]
                then
                        daysofmth=29
                else
                        daysofmth=28
                fi
        elif [ $month -eq 4 -o $month -eq 6 -o $month -eq 9 -o $month -eq 11 ]
        then
                daysofmth=30
        fi
        julday=`expr $julday - $daysofmth`
        if [ $julday -lt 0 ]
        then
                done=1
                julday=`expr $daysofmth + $julday`
        elif [ $julday -eq 0 ]
        then
                done=1
                julday=$daysofmth
        fi
}
#########  main script starts here
if [ $# -ne 1 ]
then
        echo "Usage: tonfro <delta>"
        exit 1
fi
julday=`expr \`date +%j\` + $1`
year=`date +%Y`
month=0
while [ $julday -le 0 ]
do
        year=`expr $year - 1`
        if [ `expr $year % 100` -eq 0 -a `expr $year % 400` -eq 0 ]
        then
                julday=`expr $julday + 366`
        elif [ `expr $year % 100` -ne 0 -a `expr $year % 4` -eq 0 ]
        then
                julday=`expr $julday + 366`
        else
                julday=`expr $julday + 365`
        fi
done

done=0

while [ $done -ne 1 ]
do
        month=`expr $month + 1`
        if [ $month -eq 13 ]
        then
                year=`expr $year + 1`
                month=1
        fi
        check_done
done

printf "%d-%.2d-%.2d\n" $year $month $julday

 

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CAL(1)							    BSD General Commands Manual 						    CAL(1)

NAME
cal -- displays a calendar SYNOPSIS
cal [-smjy13] [[[day] month] year] DESCRIPTION
Cal displays a simple calendar. If arguments are not specified, the current month is displayed. The options are as follows: -1 Display single month output. (This is the default.) -3 Display prev/current/next month output. -s Display Sunday as the first day of the week. -m Display Monday as the first day of the week. -j Display Julian dates (days one-based, numbered from January 1). -y Display a calendar for the current year. -V Display version information and exit. A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calen- dar for 1989. Two parameters denote the month (1 - 12) and year. Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no parameters are specified, the current month's calendar is displayed. A year starts on Jan 1. The first day of the week is determined by the locale. The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref- ormation (although a few did not recognize it until the early 1900's.) Ten days following that date were eliminated by the reformation, so the calendar for that month is a bit unusual. HISTORY
A cal command appeared in Version 6 AT&T UNIX. OTHER VERSIONS
Several much more elaborate versions of this program exist, with support for colors, holidays, birthdays, reminders and appointments, etc. For example, try the cal from http://home.sprynet.com/~cbagwell/projects.html or GNU gcal. AVAILABILITY
The cal command is part of the util-linux-ng package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux-ng/. BSD
June 6, 1993 BSD
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