Hi everyone,
I need to be able to write into a ksh script, a function that can look at 2 24 hour time variables and work out the difference between them.
e.g
job1 runs at 21:00
job2 runs at 01:00
diff = 04:00 hours
I would also need negative numbers i.e where job1 runs after job2
... (1 Reply)
Hi Friends,
When Iam running c program in redhat linux 7.3 version and PCQ Linux 8.0 version, its taking around 20 seconds. But when Iam running it in HP-UX Release 11i, its taking around 3 minutes. Can anyone throw light on this.
Thanks in advance,
Praveen. (11 Replies)
:rolleyes: Hi,
How to take the time diffence between start and finish time from a log file?
It is like
..... started at Jun 20 23:20
.
.
..... finished at Jun 21 01:40
Tryed so many ways but failed to ger exact way. :confused:
Your help will be honoured.
Ta........Lokesha (1 Reply)
Hi guys,
I know that this topic has been discuss numerous times, and I have search the net and this forum for it.
However, non able to address the problem I faced so far.
I am on Solaris Platform and unable to install additional packages like the GNU date and gawk to make use of their... (5 Replies)
I wondered if someone could point out the differences between the time commmand and usr/bin/time and the accuracy one might have over another.
Also, is there a website or two a person could maybe link for me to describe the differences?
Thank you for your time. (2 Replies)
Is there a way to tell diff to show differences one line at a time and not to group them? For example, I have two files:
file1:
line 1
line 2
line 3 diff
line 4 diff
line 5 diff
line 6
line 7
file2:
line 1
line 2
line 3 diff.
line 4 diff.
line 5 diff.
line 6
line 7 (13 Replies)
I have a cluster of two Solaris server (veritas cluster). one working and the other is standby
I am going to change the date on them , and am looking for a secure solution as it is giving an important service.
my opinion is that the active one doesn't need to be restarted (if I don't change the... (1 Reply)
I needed some help in adding a duration (in seconds) to a start time (in hhmmss format) and a start date (in mmddyy format) in order to get an end date and end time. The concept of a leap year is also to be considered while incrementing the day. The code/ function that I have formed so far is as... (3 Replies)
Hi Folks,
My server time is in EDT. And i am sending automated mails from that server in which i need to display the current date time as per IST (GMT+5:30). Please advice how to display the date time as per IST.
IST time leads 9:30 mins to EDT. and i wrote something like below.
... (6 Replies)
Good day to all.
I'm relatively new in using the Sun Solaris OS. I would like to request your expertise in helping to solve a problem that I have at work. Not sure if this has been asked before but I have tried searching through the internet to no avail.
Basically I have 2 sun solaris... (8 Replies)
Discussion started by: Fossil_84
8 Replies
LEARN ABOUT CENTOS
time::seconds
Time::Seconds(3pm) Perl Programmers Reference Guide Time::Seconds(3pm)NAME
Time::Seconds - a simple API to convert seconds to other date values
SYNOPSIS
use Time::Piece;
use Time::Seconds;
my $t = localtime;
$t += ONE_DAY;
my $t2 = localtime;
my $s = $t - $t2;
print "Difference is: ", $s->days, "
";
DESCRIPTION
This module is part of the Time::Piece distribution. It allows the user to find out the number of minutes, hours, days, weeks or years in a
given number of seconds. It is returned by Time::Piece when you delta two Time::Piece objects.
Time::Seconds also exports the following constants:
ONE_DAY
ONE_WEEK
ONE_HOUR
ONE_MINUTE
ONE_MONTH
ONE_YEAR
ONE_FINANCIAL_MONTH
LEAP_YEAR
NON_LEAP_YEAR
Since perl does not (yet?) support constant objects, these constants are in seconds only, so you cannot, for example, do this: "print
ONE_WEEK->minutes;"
METHODS
The following methods are available:
my $val = Time::Seconds->new(SECONDS)
$val->seconds;
$val->minutes;
$val->hours;
$val->days;
$val->weeks;
$val->months;
$val->financial_months; # 30 days
$val->years;
$val->pretty; # gives English representation of the delta
The usual arithmetic (+,-,+=,-=) is also available on the objects.
The methods make the assumption that there are 24 hours in a day, 7 days in a week, 365.24225 days in a year and 12 months in a year.
(from The Calendar FAQ at http://www.tondering.dk/claus/calendar.html)
AUTHOR
Matt Sergeant, matt@sergeant.org
Tobias Brox, tobiasb@tobiasb.funcom.com
BalieXXzs SzabieXX (dLux), dlux@kapu.hu
LICENSE
Please see Time::Piece for the license.
Bugs
Currently the methods aren't as efficient as they could be, for reasons of clarity. This is probably a bad idea.
perl v5.16.3 2013-03-04 Time::Seconds(3pm)