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Full Discussion: Pipelining
Top Forums Shell Programming and Scripting Pipelining Post 78253 by muthukumar on Monday 18th of July 2005 07:35:34 AM
Old 07-18-2005
You have taken correct way. $? will give status of prev command. we can not make it with single utility to give return code and redirect output to another log file. You can do it better as,

# proc > logfile
RC=$?
tee -a <logfile> < logfile
print "$RC"

where, < <filename> is faster than cat <filename>

That is all.
 

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LOGSAVE(8)						      System Manager's Manual							LOGSAVE(8)

NAME
logsave - save the output of a command in a logfile SYNOPSIS
logsave [ -asv ] logfile cmd_prog [ ... ] DESCRIPTION
The logsave program will execute cmd_prog with the specified argument(s), and save a copy of its output to logfile. If the containing directory for logfile does not exist, logsave will accumulate the output in memory until it can be written out. A copy of the output will also be written to standard output. If cmd_prog is a single hyphen ('-'), then instead of executing a program, logsave will take its input from standard input and save it in logfile logsave is useful for saving the output of initial boot scripts until the /var partition is mounted, so the output can be written to /var/log. OPTIONS
-a This option will cause the output to be appended to logfile, instead of replacing its current contents. -s This option will cause logsave to skip writing to the log file text which is bracketed with a control-A (ASCII 001 or Start of Header) and control-B (ASCII 002 or Start of Text). This allows progress bar information to be visible to the user on the console, while not being written to the log file. -v This option will make logsave to be more verbose in its output to the user. AUTHOR
Theodore Ts'o (tytso@mit.edu) SEE ALSO
fsck(8) E2fsprogs version 1.44.1 March 2018 LOGSAVE(8)
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