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Top Forums Shell Programming and Scripting need grep to output basename and line# Post 78058 by RishiPahuja on Friday 15th of July 2005 03:37:10 AM
Old 07-15-2005
MySQL

grep -n "$1" $SCCSPATH/*/s.*.k | cut -c1-80


something like this should do

Code:
for i in `ls -l $SCCSPATH/*/s.*.k`
do
dirn=`dirname $i`
filen=`basename $i`
cd $dirn
grep -n "$1" $filen | cut -c1-80
done

 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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