Sponsored Content
Top Forums Shell Programming and Scripting Passing output of sed/echo to a variable Post 77854 by zazzybob on Wednesday 13th of July 2005 09:29:52 AM
Old 07-13-2005
No probs Smilie

I think I see the problem....

I didn't use code tags and maybe the backticks look like single quotes if you haven't copied and pasted directly....

Code:
set j = `echo "$i" | sed "s/$1/$2/"`

Cheers
ZB
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

variable passing to sed

I m trying to pass variable to sed. export var=140920060731 sed -e '/$var/d' file but no luch so far..? any body has any idea abt it Is there any way to pass variable to SED? Thanks , Manish (2 Replies)
Discussion started by: Manish Jha
2 Replies

2. Shell Programming and Scripting

Passing output to variable instead of file

Hi, In normal shell scripting, how do you pass the output of a command to a variable, instead of a file and be able to use it later? The code is: #!/bin/bash who | cut -d" " -f1 > onlineusers Instead of passing the output of the above command to the file called 'onlineusers'... (1 Reply)
Discussion started by: Furqan_79
1 Replies

3. Shell Programming and Scripting

Passing Variable in sed

Dear All, I want to print a file. First I tried with this sed '2q;d' filename it worked. But when i put following it is not working x=2; sed '$xq;d' filename Would any one suggest how to pass the variable? (7 Replies)
Discussion started by: saifurshaon
7 Replies

4. Shell Programming and Scripting

storing output from echo & cut into variable

Hi All, Hope someone can advise here as I have been struggling to find a syntax that works here. I have tried a stack of combination I have seed in the forums but I think because I have needed to use "" and `` in the statments another method is found. I am reading in lines with the following... (1 Reply)
Discussion started by: nkwilliams
1 Replies

5. Shell Programming and Scripting

Problem with variable ECHO $((SED...

Hi, I'm new here so I want to say hello to everyone first! I searched google and this forum for a similar problem, but wasn't successful #! /bin/bash I'm trying to output (echo) n lines of a text file to the screen (later into another file). But I have problem with the sed command, it won't... (1 Reply)
Discussion started by: studiologe
1 Replies

6. Shell Programming and Scripting

cannot pass a echo output to a variable in bash

Hi, I have a problem with passing a echo output into a variable in bash file='1990.tar' NAME='echo $file | cut -d '.' -f1'; echo $NAME the result is echo $file | cut -d . -f1 however with this one,#!/bin/bash file='1990.tar' echo $file | cut -d '.' -f1 the result is what I... (2 Replies)
Discussion started by: 1988PF
2 Replies

7. Shell Programming and Scripting

Sending Sed/Echo output to Variable

I have a variable $WORDS that contains a string Then i want to use sed to break it up. echo $WORDS | sed 's// /g' I tried setting this as a variable by doing WORDS2=`echo $WORDS | sed 's// /g'` But when i do this it does not return me to the prompt properly ie. jmpprd-v1> jmpprd-v1>... (4 Replies)
Discussion started by: nitrobass24
4 Replies

8. Shell Programming and Scripting

Echo awk output from its variable

Stumped with the formatting of the awk output when used with variables, e.g.: awk -F, 'BEGIN {OFS=","} print {$2,$3,$4}' $infile1 produces the desired output (with rows), but when echoing the variable below, the output is one continuous line var1=$(awk -F, 'BEGIN {OFS=","} print... (4 Replies)
Discussion started by: ux4me
4 Replies

9. UNIX for Dummies Questions & Answers

Passing value of a variable in sed

Hi, I want to pass value of a variable track_line which is the line number to sed. Sed should print the lines starting from track_line till the last line of the file. I tried the below command but it is not working. sed -n '${track_line},$p' latest_log_file I tried using the below too but... (1 Reply)
Discussion started by: nitinupadhyaya8
1 Replies

10. UNIX for Advanced & Expert Users

Passing variable as input & storing output in other variable

I have a below syntax its working fine... var12=$(ps -ef | grep apache | awk '{print $2,$4}') Im getting expected output as below: printf "%b\n" "${VAR12}" dell 123 dell 456 dell 457 Now I wrote a while loop.. the output of VAR12 should be passed as input parameters to while loop and results... (5 Replies)
Discussion started by: sam@sam
5 Replies
echo(1) 						      General Commands Manual							   echo(1)

NAME
echo - echo (print) arguments SYNOPSIS
[arg] ... DESCRIPTION
writes its arguments separated by blanks and terminated by a new-line on the standard output. It also understands C-like escape conven- tions; beware of conflicts with the shell's use of write an alert character backspace print line without appending a new-line form-feed new-line carriage return tab vertical tab backslash the 8-bit character whose ASCII code is the 1-, 2-, 3- or 4-digit octal number n, whose first character must be a zero. write an 8-bit value that is the zero-, one-, two- or three-digit octal number num is useful for producing diagnostics in command files and for sending known data into a pipe. Notes Berkeley differs from this implementation. The former does not implement the backslash escapes. However, the semantics of the escape can be obtained by using the option. The echo command implemented as a built-in function of follows the Berkeley semantics (see csh(1)). EXTERNAL INFLUENCES
Environment Variables determines the interpretation of arg as single and/or multi-byte characters. If is not specified in the environment or is set to the empty string, the value of is used as a default for each unspecified or empty vari- able. If is not specified or is set to the empty string, a default of "C" (see lang(5)) is used instead of If any internationalization variable contains an invalid setting, behaves as if all internationalization variables are set to "C". See environ(5). International Code Set Support Single- and multi-byte character code sets are supported. AUTHOR
was developed by OSF and HP. SEE ALSO
sh(1). BUGS
No characters are printed after the first This is not normally a problem. STANDARDS CONFORMANCE
echo(1)
All times are GMT -4. The time now is 01:38 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy