I am calling an oracle function that returns a number (either 0 or 2), how do I pass that pass to the wrapping shell script as I would like to do other things based on the value returned by the oracle function.
Assign a variable to the sqlplus call. I belive you do not need to assign the
return code.
This is how I would do it:
Then I evaluate the variable to get the results or see if an error occured. You should see what the df_validate_file returns or an error if one occured.
Hi ,
i am beginner to Unix, I have one small script which execute java programme,it has java command input output structure . Right now i have given Input output structure manually that is on same directory, now how can i pass that by commandline
#!/bin/sh
java Classjava input.txt... (5 Replies)
Hi,
I have a shell script with an ambedded awk script.
i need to pass a script variable to the awk script.
Please help.
Thanks in advance
Himani (3 Replies)
I am passing a varaible to from Shell to awk then I am doing some maniplation for that variable inside awk. I want that maniplated variable value back to shell , Is this possible .Please let me know. (12 Replies)
Hello Experts,
Actually I was searching for a solution here in this forum , but didn't get what exactly I want . Is this possible to do in awk ?
I am trying to do some thing like below in ksh script . Upto my knowledge I can pass shell script to awk with "-v " option.
But I... (3 Replies)
i had this unix korn shell code that connects to oracle database and execute the oracle procedure. i need to add a variable that indicates the oracle procedure failed. basically the variable is to check if the oracle procedure failed it will assign 1 and when the variable is equal to 1 it will not... (4 Replies)
I have a shell script (.sh) and I want to pass a parameter value to the awk command but I am getting exception, please assist.
diff=$1$2.diff
id=$2 new=new_$diff
echo "My id is $1"
echo "I want to sync for user account $id"
##awk command I am using is as below
cat $diff | awk... (2 Replies)
Hello,
I am trying to execute an SQL query from shell script.
A part of script is something like this:
fromDate=`echo $(date +"%F%T") | sed "s/-//g" | sed "s/://g"`
$ORACLE_HOME/sqlplus -s /nolog <<EOD1
connect $COSDBUID/$COSDBPWD@$COSDBSID
spool... (4 Replies)
Hi all,
$ echo $SHELL
/bin/bash
Requirement - How to pass oracle sql script as argument to unix shell script?
$ ./output.sh users.sql
Below are the shell scripts and the oracle sql file in the same folder.
Shell Script
$ cat output.sh
#!/bin/bash
.... (7 Replies)
Hi all,
Hopefully you can help. This is what I'm trying to achieve:
Obtain a list of usernames out of an Oracle Database
Based on this list, link each username with an Oracle Internet Directory (OID) GUID
Using the username and GUID perform a database update for all users
Here are the... (7 Replies)
Discussion started by: exm
7 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)