06-16-2005
Quote:
Originally Posted by Javi
The command 'lsof' doesn't show the file that the 'vsftpd' process is writting. I get the same problem with 'fuser'.
I have made a C program that lock in exclusive mode the file. I thought that If I am able to lock the file then the file is not open by another process. But It doesn't work, the program is able to lock the file although the file is downloading.
The real problem appear to be that, nowhere in the Linux system reside information about the files than the vsftpd daemon is working with ...
Re paragraph 1: I find it very hard to believe that lsof can't do this. Your lsof could be broken, more more likely you are doing something wrong. Since you haven't mentioned stuff like precisely what command you used or precisely what result you got there's no way to tell. Could you take a bug report like: "'lsof' doesn't show the file" and do anything with it?
Re paragraph 2: "exclusive locks" are the only kind that exist. If you want a mandatory lock, read
mandatory.txt. But this won't help much. If you do it correctly, you will succeed, and vxftpd will experience failed writes. It will probably detect this and inform the ftp client of the error.
Re paragraph 3: I wonder how the data gets to the file?
I looked at the source code for vsftpd. I see it has a logging option. Turn that on and parse the log to see if the file is finished.
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PLDD(1) Linux User Manual PLDD(1)
NAME
pldd - display dynamic shared objects linked into a process
SYNOPSIS
pldd PID
pldd OPTION
DESCRIPTION
The pldd command displays a list of the dynamic shared objects that are linked into the process with the specified process ID. The list
includes the libraries that have been dynamically loaded using dlopen(3).
OPTIONS
-?, --help
Display program help message.
--usage
Display a short usage message.
-V, --version
Display the program version.
VERSIONS
pldd is available since glibc 2.15.
CONFORMING TO
The pldd command is not specified by POSIX.1. Some other systems have a similar command.
EXIT STATUS
On success, pldd exits with the status 0. If the specified process does not exist, the user does not have permission to access its dynamic
shared object list, or no command-line arguments are supplied, pldd exists with a status of 1. If given an invalid option, it exits with
the status 64.
EXAMPLE
$ echo $$ # Display PID of shell
1143
$ pldd $$ # Display DSOs linked into the shell
1143: /usr/bin/bash
linux-vdso.so.1
/lib64/libtinfo.so.5
/lib64/libdl.so.2
/lib64/libc.so.6
/lib64/ld-linux-x86-64.so.2
/lib64/libnss_files.so.2
NOTES
The command
lsof -p PID
also shows output that includes the dynamic shared objects that are linked into a process.
SEE ALSO
ldd(1), lsof(1), dlopen(3), ld.so(8)
GNU
2014-09-27 PLDD(1)