06-13-2005
correct syntax for using "grep regex filename" ?
I'm trying to grep a long ls by looking at the beginning of each filename for example:
Many files begin with yong_ho_free_2005...
Many files begin with yong_ho_2005...
I can't just use "grep yong_ho" otherwise It'll display both files.
So I'm trying to use a regex but my syntax is wrong.
ls -al | grep '^yong_ho_[1-9]'
This displays no matches.
Anyone know what I'm doing wrong?
It works if I remove the ^ carat...
How come I can't anchor it?
Last edited by yongho; 06-13-2005 at 03:32 PM..
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ZGREP(1) General Commands Manual ZGREP(1)
NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)
ZGREP(1)