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Top Forums UNIX for Dummies Questions & Answers cal Post 72790 by victorvvk on Tuesday 24th of May 2005 08:08:16 AM
Old 05-24-2005
Bug Calendar which displays the specified months

I have Created a script known as mycal.sh , this is the contents of this script


y=`date '+ %Y' `
echo $1 > file1
tr "a-z" "A-Z" < file1 > az
n=1
ch=`cut -c$n az`

while test "$ch" != "-"
do
f=$f$ch
n=`expr $n + 1`
ch=`cut -c$n az`
done
n=`expr $n + 1`
s=`cut -c$n- az`
for i in $f $s
do
case $i in
JAN) m=1;;
FEB) m=2;;
MAR) m=3;;
APR) m=4;;
MAY) m=5;;
JUN) m=6;;
JUL) m=7;;
AUG) m=8;;
SEP) m=9;;
OCT) m=10;;
NOV) m=11;;
DEC) m=12;;
esac
if [ "$i" = "$f" ]
then
fm=$m
fi
done
if [ $fm -gt $m ]
then
echo "Invalid Range"
fi
while [ $fm -le $m ]
do
cal $fm $y
fm=`expr $fm + 1`
done

save it and run the script by executing this at the command line

sh mycal.sh MAR-JUN


( Likewise you can give as many number of month combination
example
JAN-MAR
MAR-MAY
JAN-DEC ....... etc..

Enjoy
 

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EXPR(1) 						      General Commands Manual							   EXPR(1)

NAME
expr - evaluate arguments as an expression SYNOPSIS
expr arg ... DESCRIPTION
The arguments are taken as an expression. After evaluation, the result is written on the standard output. Each token of the expression is a separate argument. The operators and keywords are listed below. The list is in order of increasing precedence, with equal precedence operators grouped. expr | expr yields the first expr if it is neither null nor `0', otherwise yields the second expr. expr & expr yields the first expr if neither expr is null or `0', otherwise yields `0'. expr relop expr where relop is one of < <= = != >= >, yields `1' if the indicated comparison is true, `0' if false. The comparison is numeric if both expr are integers, otherwise lexicographic. expr + expr expr - expr addition or subtraction of the arguments. expr * expr expr / expr expr % expr multiplication, division, or remainder of the arguments. expr : expr The matching operator compares the string first argument with the regular expression second argument; regular expression syntax is the same as that of ed(1). The (...) pattern symbols can be used to select a portion of the first argument. Otherwise, the matching operator yields the number of characters matched (`0' on failure). ( expr ) parentheses for grouping. Examples: To add 1 to the Shell variable a: a=`expr $a + 1` To find the filename part (least significant part) of the pathname stored in variable a, which may or may not contain `/': expr $a : '.*/(.*)' '|' $a Note the quoted Shell metacharacters. SEE ALSO
ed(1), sh(1), test(1) DIAGNOSTICS
Expr returns the following exit codes: 0 if the expression is neither null nor `0', 1 if the expression is null or `0', 2 for invalid expressions. EXPR(1)
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