05-09-2005
var=`echo $var | sed 's/.*\.//'`
Last edited by bhargav; 05-10-2005 at 12:03 AM..
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1. Shell Programming and Scripting
HOw can I use any variable in sed command.
For example I am using 'sed -e 's/?/$ORACLE_HOME/g' $file_name
Here it replaces ? with $ORACLE_HOME. Instead of it I need actual value of $ORACLE_HOME. How can I do that?
Please advice.
Thanks in advance.
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2. Shell Programming and Scripting
Hi,
My shell script searches a VALUE in a file, copies it to a variable and updates a line in another file with this new VALUE (replacing the old)
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VALUE=`$$MyDate=11-11-2008 09.09.56.123456`
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3. Shell Programming and Scripting
Hello,
i have another sed question.. I'm trying to do variable substition with sed and i'm running into a problem.
my var1 is a string constructed like this:
filename1 filerev1 filepath1
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4. Shell Programming and Scripting
i need to use a value in the Variable to print a particular line from a file using sed command.
i tried the below one but its is not working
sed -n ' "$var"p ' abc.txt
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5. Shell Programming and Scripting
I want to instert Category:XXXXX into the 2. line
something like this should work, but I have somewhere the wrong sytanx. something with the linebreak goes wrong:
sed "2i\\${n}Category:$cat\n"
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Titel Blahh Blahh abllk sdhsd sjdhf
Blahh Blah Blahh
Blahh
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6. Shell Programming and Scripting
I'm trying to make a sed substitution where the substitution pattern is an environment variable to be expanded, but the variable contains a "slash".
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7. Shell Programming and Scripting
Hi Friends
in sed whether we can use variable.like the following expression.
sed -i 's/ABC/$var/g' filename
I am using Kernel 2.6.18-194.11.1.el5 RedHat linux.
I have tried sed -i 's/ABC/"$var"/g' filename, still not working.:(
Please help.
Thanks in advance
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8. Shell Programming and Scripting
Hello
i would like to interpret a variable in this command
cnt=3
sed -n '${cnt}p' file.txt
sed: 0602-403 `${cnt}`p is not a recognized function.
can you help me please ?
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Hi all,
Hereby wish to have your advise for below:
Main concept is
I intend to get current directory of my script file.
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Below is original script file:
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10. Shell Programming and Scripting
version=git
release=r8
echo lp-testsuite-git-r8.x86_64.rpm |sed -e "s/-$version-$release.*//g"
I want to get
lp-testsuite
what's wrong with me ? (1 Reply)
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LEARN ABOUT MOJAVE
escape
escape(1) Mail Avenger 0.8.3 escape(1)
NAME
escape - escape shell special characters in a string
SYNOPSIS
escape string
DESCRIPTION
escape prepends a "" character to all shell special characters in string, making it safe to compose a shell command with the result.
EXAMPLES
The following is a contrived example showing how one can unintentionally end up executing the contents of a string:
$ var='; echo gotcha!'
$ eval echo hi $var
hi
gotcha!
$
Using escape, one can avoid executing the contents of $var:
$ eval echo hi `escape "$var"`
hi ; echo gotcha!
$
A less contrived example is passing arguments to Mail Avenger bodytest commands containing possibly unsafe environment variables. For
example, you might write a hypothetical reject_bcc script to reject mail not explicitly addressed to the recipient:
#!/bin/sh
formail -x to -x cc -x resent-to -x resent-cc
| fgrep "$1" > /dev/null
&& exit 0
echo "<$1>.. address does not accept blind carbon copies"
exit 100
To invoke this script, passing it the recipient address as an argument, you would need to put the following in your Mail Avenger rcpt
script:
bodytest reject_bcc `escape "$RECIPIENT"`
SEE ALSO
avenger(1),
The Mail Avenger home page: <http://www.mailavenger.org/>.
BUGS
escape is designed for the Bourne shell, which is what Mail Avenger scripts use. escape might or might not work with other shells.
AUTHOR
David Mazieres
Mail Avenger 0.8.3 2012-04-05 escape(1)