I do ls -l ABC*, I get arg list too long message. This will not happen if ABC* has small no of files I believe 4000 files is limit. Any way of avoiding this.
I even tried like this
for i in `ls -l ABC*`
do
echo $i
done
Same problem.
Any solution would be great.
I am on HP-UX... (5 Replies)
hi everyone,
We have a heck of a lot of files in a particular directory and I need to search through all of them to find a list of all files containing particular text strings...one being a date and the other being the name of the report that is printed on the files.....
I've tried the... (6 Replies)
Hi all
I have more than 1000 files in a folder and when ever i use a "compress" or "zcat" command it give error
/bin/zcat: Arg list too long. .
any solution for this :o (3 Replies)
hello all
i need some help because i am a unix/linux dummy...i have the following:
DIR1> has 121437 files in it with varying dates going back to early April,
a sub dir DIR1/DIR2> has 55835 files in it
I need to move all files (T*.*) out of DIR1 into DIR2 that are older than today?
Ive been... (2 Replies)
Hi,
I am trying to perform this task:
tar -cvf tar.newfile ??????.bas
I got error "arg list too long". Is ther any way around? I have about 1500 file need to be tar together.
Thanks in advance (5 Replies)
Hey guys. I have a program written in which i am trying to get the files from one remote machine and transferring the files to another remote machine using SCP.
It works fine for 50 or 60 files but when the files grows to 250 then i get an error message stating "Arg list too long".
#scp -p... (5 Replies)
Hi,
Help. I have a file that contains a list of users in a file. I want to cat the content of the file and feed it into sed to a preformated report. The error I got is "ksh: /usr/bin/sed: arg list too long" My method below.
A=`cat FILE1.txt`
B=`echo $A`
sed "s#USERLIST#$B#" FILE2 >... (2 Replies)
Hello,
I'm trying to search through 30,000 files in 1 directory, and am getting the "arg list too long" error. I've searched this forum and have been playing around with xargs and can't get that to work either. I'm using ksh on Solaris.
Here's my original code:
nawk "/Nov 21/{_=2}_&&_--"... (14 Replies)
Hello All,
I am trying to find a file name with .sh exention from a list of .dat files inside a directory.
find /app/folder1/* -name '*.dat'| xargs grep '.sh'
ksh: /usr/local/bin/find: arg list too long
Please help me finding the command.
Thanks (3 Replies)
Discussion started by: tkhan9
3 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)