09-17-2001
Date function question
hi guys!
just want to ask if you could help me with the sript i'm working on. i need to automatically generate a summarized report everyday for all transactions the day before and ftp it to another machine. my only problem is that i need to name the file as the date yesterday. for example if i would generate a report today (09172001), the filename should be 09162001.txt, i've read the man for date but i haven't got a clue as to what to do.
please help.
thanks!
Last edited by crpalermo; 09-17-2001 at 03:23 AM..
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LEARN ABOUT PLAN9
yesterday
YESTERDAY(1) General Commands Manual YESTERDAY(1)
NAME
yesterday - print file names from the dump
SYNOPSIS
yesterday [ -c ] [ -date ] files ...
DESCRIPTION
Yesterday prints the names of the files from the most recent dump. Since dumps are done early in the morning, yesterday's files are really
in today's dump. For example, if today is March 17, 1992,
yesterday /adm/users
prints
/n/dump/1992/0317/adm/users
In fact, the implementation is to select the most recent dump in the current year, so the dump selected may not be from today.
With option -c, yesterday copies the dump file to the current directory.
The date option selects other day's dumps, with a format of 2, 4, 6, or 8 digits of the form dd, mmdd, yymmdd, or yyyymmdd.
Yesterday does not guarantee that the string it prints represents an existing file.
EXAMPLES
Back up to yesterday's MIPS binary of vc:
cd /mips/bin
yesterday -c vc
Temporarily back up to March 1's MIPS C library to see if a program runs correctly when loaded with it:
bind `{yesterday -0301 /mips/lib/libc.a} /mips/lib/libc.a
rm v.out
mk
v.out
FILES
/n/dump
SOURCE
/rc/bin/yesterday
SEE ALSO
fs(4)
BUGS
It's hard to use this command without singing.
YESTERDAY(1)