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Full Discussion: search and Replace
Top Forums UNIX for Advanced & Expert Users search and Replace Post 6874 by LivinFree on Friday 14th of September 2001 03:39:58 AM
Old 09-14-2001
I was just thinking about it, and I guess this isn't the most helpful was to explain this. I'm going to add some comments (in bold) to the code, so you can see what's happening step by step:
Quote:
Originally posted by LivinFree
Code:
#!/bin/sh
# check.sh
# This script takes two arguments -
# The first is the word you a looking for,
# and the second is the file you want to find
# the word in.
# Example: check.sh lamb haggis
# Will look for the word "lamb" in the file "haggis"
# This is to make sure there are exactly two arguments
# passed to the script. If not, it will give you a little hint...
# The "$#" counts the number of aguments, and -ne is the same
# as saying "not equal".
if [ "$#" -ne "2" ] ; then
     echo "Usage: "
     echo "`basename $0` {search string} {file} "
     exit 2
fi
[/b]# Right here, we check to make sure the file we are searching
# exists, and is a regular file. For more information on the -f
# statement, use the 'man test' command.[/b]
if [ -f "$2" ] ; then
# We don't actually want to see the results of the search,
# we only want to know if it was successful, so we send the
# output to /dev/null - to nowhere-land
grep "$1" $2 > /dev/null 
# The "$?" construct tells you the status of the last command.
# if $? is equal to zero, the command was successful, if it is any
# number other than 0, there was a problem
case $? in
     0) echo -e "\nThe word \"$1\" was found in the \"$2\" file! \n" ;;
     *) echo -e "\nThe word \"$1\" was NOT found in the \"$2\" file! \n" ;;
esac
exit 0
# This is what happens if the file did not exist (see above)
# This is our backup plan - it keeps grep from getting "stuck"
# if there is no file
else
echo "The \"$2\" file does not exist"
exit 2
fi

The exit 0 tells it to exit successfully (remember $?), and exit 2 tells it that there were errors, and to exit right away. I hope this is a little more helpful
This is one of many ways to do it...
By saying this is one of many, I mean it - here is an example of a one-liner that will do nearly the same thing without the error handling or variables:
Code:
grep lamb haggis > /dev/null && echo Word found in file || echo Word NOT found in file

As you can see, the "grep" command is the same as in the script, but the messages are handled differently. The commands after the "&&" will execute if the previous command was successful, and the command after the "||" will execute if it was not successful.

Geez, I'd make a horrible teacher...

Last edited by LivinFree; 09-14-2001 at 04:54 AM..
 

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CUBRID_IS_INSTANCE(3)							 1						     CUBRID_IS_INSTANCE(3)

cubrid_is_instance - Check whether the instance pointed by OID exists

SYNOPSIS
int cubrid_is_instance (resource $conn_identifier, string $oid) DESCRIPTION
The cubrid_is_instance(3) function is used to check whether the instance pointed by the given $oid exists or not. PARAMETERS
o $conn_identifier -Connection identifier. o $oid -OID of the instance that you want to check the existence. RETURN VALUES
1, if such instance exists; 0, if such instance does not exist; -1, in case of error EXAMPLES
Example #1 cubrid_is_instance(3) example <?php $conn = cubrid_connect("localhost", 33000, "demodb"); $sql = <<<EOD SELECT host_year, medal, game_date FROM game WHERE athlete_code IN (SELECT code FROM athlete WHERE name='Thorpe Ian'); EOD; $req = cubrid_execute($conn, $sql, CUBRID_INCLUDE_OID); $oid = cubrid_current_oid($req); $res = cubrid_is_instance ($conn, $oid); if ($res == 1) { echo "Instance pointed by $oid exists. "; } else if ($res == 0){ echo "Instance pointed by $oid doesn't exist. "; } else { echo "error "; } cubrid_disconnect($conn); ?> The above example will output: Instance pointed by @0|0|0 doesn't exist. SEE ALSO
cubrid_drop(3), cubrid_get_class_name(3). PHP Documentation Group CUBRID_IS_INSTANCE(3)
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