Sponsored Content
Top Forums Shell Programming and Scripting ksh: A part of variable A's name is inside of variable B, how to update A? Post 67831 by vgersh99 on Monday 28th of March 2005 03:16:15 PM
Old 03-28-2005
Quote:
Originally Posted by pa3be
This is what I tried:

vara=${varb}_count
(( vara += 1 ))


Thanks for help
hmm.... this is one confusing explanation.
what are you trying to do?
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

How to replace variable inside the variable

hi sir, i need your help for this script inside /rnmucdr/ednms05/ken/xMNBDF045_Script.sql content variable like this select * from invoice where bill_date=$BILLDATE and startNum=$STARTPARTNNUM and total_partn=$TOTALPARTN if i just paste this replace with the $SCRIPT it works great,if... (31 Replies)
Discussion started by: mani_um
31 Replies

2. UNIX for Dummies Questions & Answers

passing a variable inside a variable to a function

I would like to know how to pass a variable inside a variable to a function. sample code below -------------- for x in 1 9 do check_null $C$x ##call function to check if the value is null if then echo "line number:$var_cnt,... (2 Replies)
Discussion started by: KingVikram
2 Replies

3. Shell Programming and Scripting

passing a variable inside another variable.

Any help would be great. I know this is a dumb way of doing this, but I would like to know if there is a solution doing it this way. I'm very new at this and I'd like to learn more. Thanks! :D:D count=0 while ; do echo "enter your name" read name_$count let count=count+1 done ... (2 Replies)
Discussion started by: reconflux
2 Replies

4. Shell Programming and Scripting

variable inside variable inside loop headache

Hi Gurus I have a file called /tmp/CMDB which looks like this serial: 0623AN1208 hostname: server1 model: x4100 assetID: 1234 I am writing a for loop that will go through this file line by line creating a variable of itself. Using the first iteration of the loop (i.e. the first line) as... (6 Replies)
Discussion started by: hcclnoodles
6 Replies

5. Shell Programming and Scripting

how to pass a variable to an update sql statement inside a loop

hi all, i am experiencing an error which i think an incorrect syntax for the where clause passing a variable was given. under is my code. sqlplus -s ${USERNAME}/${PASSWORD}@${SID} << END1 >> $LOGFILE whenever sqlerror exit set serveroutput on size 1000000 declare l_rc ... (0 Replies)
Discussion started by: ryukishin_17
0 Replies

6. Shell Programming and Scripting

Not able to store command inside a shell variable, and run the variable

Hi, I am trying to do the following thing var='date' $var Above command substitutes date for and in turn runs the date command and i am getting the todays date value. I am trying to do the same thing as following, but facing some problems, unique_host_pro="sed -e ' /#/d'... (3 Replies)
Discussion started by: gvinayagam
3 Replies

7. Shell Programming and Scripting

Variable to command to Variable Question KSH

Hello, First post for Newbie as I am stumped. I need to get certain elements for a specific PID from the ps command. I am attempting to pass the value for the PID I want to retrieve the information for as a variable. When the following is run without using a variable, setting a specific PID,... (3 Replies)
Discussion started by: Coyote270WSM
3 Replies

8. Shell Programming and Scripting

Resolve variable inside another variable

Hello Everyone, I am trying to resolve a variable inside another variable.Let me go straight to the example. Input: Query=$Table_1 Join $Table_2 (Query itself is a variable here) Now for two different cases I am assigning different values to Table_1 and Table_2 Case 1:... (14 Replies)
Discussion started by: vinay4889
14 Replies

9. Shell Programming and Scripting

Return value inside isql to a shell variable in ksh

Hello, I have a shell script where I am doing an isql to select some records. the result i get from the select statement is directed to an output file. I want to assign the result to a Shell variable so that I can use the retrieved in another routine. e.g. "isql -U${USER} -P${PASSWD} -S${SERVER}... (1 Reply)
Discussion started by: RookieDev
1 Replies

10. Shell Programming and Scripting

To print value for a $variable inside a $variable or file

Hi guys, I have a file "abc.dat" in below format: FILE_PATH||||$F_PATH TABLE_LIST||||a|b|c SYST_NM||||${SRC_SYST} Now I am trying to read the above file and want to print the value for above dollar variables F_PATH and SRC_SYST. The problem is it's reading the dollar variables as... (5 Replies)
Discussion started by: abcabc1103
5 Replies
SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
All times are GMT -4. The time now is 04:30 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy