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Full Discussion: getopts
Top Forums Shell Programming and Scripting getopts Post 67716 by google on Saturday 26th of March 2005 09:04:23 AM
Old 03-26-2005
I didnt test this at all, just a thought I had. Im sure there are a million ways to do this.

Code:
USAGE="Usage: `basename $0` [-s schemaname] [-d databasename] [-u username] -f -t -h"
while getopts :s:d:u:fth params
do
   case $params in
     s) SOURCESCHEMA="$OPTARG"
        let COUNT= $COUNT+10000
         ;;
     f) FULL='y'
         ;;

     t) TABLE='y'
         ;;

     d) DBNAME="$OPTARG"
         let COUNT= $COUNT+1
        ;;

     u) USERNAME="$OPTARG"
         let COUNT= $COUNT+1000
         ;;
     h) 
         help_doc
         exit 0 
         ;;
     ?) 
         echo "Invalid Option Specified"
         echo "$USAGE" 1>&2 ; exit 1 
         ;;
   esac

if [ "$COUNT" -ne 10101 ]
  then
    help_doc
    exit 0
elif [ ! -z $FULL ]
   then
      echo "Paramater FULL is Set"
elif [ ! -z $TABLE ]
   then
      echo "Paramater TABLE is Set"
else
    echo "Neither TABLE or FULL Are Set"
fi

 

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DATEFMT_GET_PATTERN(3)							 1						    DATEFMT_GET_PATTERN(3)

IntlDateFormatter::getPattern - Get the pattern used for the IntlDateFormatter

	Object oriented style

SYNOPSIS
public string IntlDateFormatter::getPattern (void ) DESCRIPTION
Procedural style string datefmt_get_pattern (IntlDateFormatter $fmt) Get pattern used by the formatter. PARAMETERS
o $fmt - The formatter resource. RETURN VALUES
The pattern string being used to format/parse. EXAMPLES
Example #1 datefmt_get_pattern(3) example <?php $fmt = datefmt_create( 'en_US', IntlDateFormatter::FULL, IntlDateFormatter::FULL, 'America/Los_Angeles', IntlDateFormatter::GREGORIAN, 'MM/dd/yyyy' ); echo 'pattern of the formatter is : ' . datefmt_get_pattern($fmt); echo 'First Formatted output with pattern is ' . datefmt_format($fmt, 0); datefmt_set_pattern($fmt,'yyyymmdd hh:mm:ss z'); echo 'Now pattern of the formatter is : ' . datefmt_get_pattern($fmt); echo 'Second Formatted output with pattern is ' . datefmt_format($fmt, 0); ?> Example #2 OO example <?php $fmt = new IntlDateFormatter( 'en_US', IntlDateFormatter::FULL, IntlDateFormatter::FULL, 'America/Los_Angeles', IntlDateFormatter::GREGORIAN, 'MM/dd/yyyy' ); echo 'pattern of the formatter is : ' . $fmt->getPattern(); echo 'First Formatted output is ' . $fmt->format(0); $fmt->setPattern('yyyymmdd hh:mm:ss z'); echo 'Now pattern of the formatter is : ' . $fmt->getPattern(); echo 'Second Formatted output is ' . $fmt->format(0); ?> The above example will output: pattern of the formatter is : MM/dd/yyyy First Formatted output is 12/31/1969 Now pattern of the formatter is : yyyymmdd hh:mm:ss z Second Formatted output is 19690031 04:00:00 PST SEE ALSO
datefmt_set_pattern(3), datefmt_create(3). PHP Documentation Group DATEFMT_GET_PATTERN(3)
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