Hi
I need a script to get "Last working day of the month". I will pass the month and year as parameters and i need to get the last working date.
Ex
for June 2008 the last working day is 30th its monday.
for August 2008 the last working day is 29th and it is Friday.
ie the last working... (6 Replies)
Hi,
I want a script(ksh) to see if today is the last working day(Mon-Fri) of the month. If it is the last working day I need to print current date, else I need the last working day of previous month. Thanks in advance. (1 Reply)
Hi All,
I need to find the previous month last day minus one day, using shell script. Can you guys help me to do this.
My Requirment is as below:
Input for me will be 2000909(YYYYMM)
I need the previous months last day minus 1 day timestamp. That is i need 2000908 months last day minus ... (3 Replies)
I am using the code below modified from a post I saw here regarding having the script write out future dates. The problem is that instead of making 8/1 it makes 7/32! Please help!
yy=`date +%Y`
mm=`date +%m`
dd=`date +%d`
echo "Today is : $yy $mm $dd"
#!/usr/bin/ksh
date '+%m... (5 Replies)
Hi,
How to find the first working day of month ?
My requirement is, I need to call the function only if today is first working day of month. I could find out one function which finds last working day in month in this forum. Can anyone pls let me know for first working day. Thanks.
for... (10 Replies)
Hello All,
I am trying to come up with a shell script to count a specific word in a logfile on each day of this month, last month and the month before. I need to produce this report and email it to customer.
Any ideas would be appreciated! (5 Replies)
Hello Guys,
I have a questions regarding running a shell script every second working day each month.
I have no clue how solve this problem :wall:.
Important is that it has to be the second working (Mo-Fr).
Example: If 1st and 2nd Days of month are Sat and Sun the script must run on 4th day... (5 Replies)
Hi,
I would like to calculate 1st working/Business day of each month.
Exp:
1st -Oct-2011 is Saturday--- Non Business Day
So the Next Working Day would be 3-Oct-2011
I need a shell script to calculate the month first business date. (3 Replies)
hello,
I have many files called day001, day002, day003 and I want to rename them by day20070101, day20070102, etc.
I need to do it for several years and leap years as well.
What is the best way to do it ?
Thank you. (1 Reply)
Discussion started by: Ggg
1 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)