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Top Forums Shell Programming and Scripting Another question on awk - Begin statement Post 65887 by eff_cee on Wednesday 9th of March 2005 11:39:10 PM
Old 03-10-2005
Larry, Thanks for the prompt reply !

Interesting. Getting closer. I had to put back the line you moved (length($15) > 30 as your version would result in all records in $INPUTFILE getting output . I've simplified the code too . So now I have :

awk -F, 'BEGIN {if( length($15) > 30 ) print "HEADING RECORD"} \
length($15) > 30 \
{print $1","$3","$15, ++n \
} END {print "RECORD COUNT IS: " n}' $INPUTFILE > $TEXTFILE

BUT the if condition you moved to straight after the begin is not getting tested properly. ie the title "HEADING RECORD" is not being output (but the main body of the output is correct) Any ideas ?
 

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PRINT(3)								 1								  PRINT(3)

print - Output a string

SYNOPSIS
int print (string $arg) DESCRIPTION
Outputs $arg. print is not actually a real function (it is a language construct) so you are not required to use parentheses with its argument list. PARAMETERS
o $arg - The input data. RETURN VALUES
Returns 1, always. EXAMPLES
Example #1 print examples <?php print("Hello World"); print "print() also works without parentheses."; print "This spans multiple lines. The newlines will be output as well"; print "This spans multiple lines. The newlines will be output as well."; print "escaping characters is done "Like this"."; // You can use variables inside a print statement $foo = "foobar"; $bar = "barbaz"; print "foo is $foo"; // foo is foobar // You can also use arrays $bar = array("value" => "foo"); print "this is {$bar['value']} !"; // this is foo ! // Using single quotes will print the variable name, not the value print 'foo is $foo'; // foo is $foo // If you are not using any other characters, you can just print variables print $foo; // foobar print <<<END This uses the "here document" syntax to output multiple lines with $variable interpolation. Note that the here document terminator must appear on a line with just a semicolon no extra whitespace! END; ?> NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. SEE ALSO
echo(3), printf(3), flush(3), Heredoc syntax. PHP Documentation Group PRINT(3)
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