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Full Discussion: Some interesting questions
Top Forums UNIX for Dummies Questions & Answers Some interesting questions Post 64916 by Perderabo on Wednesday 2nd of March 2005 05:59:24 PM
Old 03-02-2005
For some of this, it's not clear what you want. For many signals, the default action is to terminate the process. This means the kernel kills it pretty much as if the process had called exit(). Some signals can be "caught". This means that a function runs instead. Well behaved processes catch signals and clean up temp files, release resources, etc. But a process cannot catch 9. 9 will instantly kill a process (if it's killable).

A pipe, you write data on one side and read the data from the other side. What else do you want here?

process1 | process2
Kill either process and nothing at all happens to the other process. However the pipe is broken. If process1 dies, the next time that process2 tries a read from the pipe, it will get eof. Many programs will decide to exit at this point. If process2 dies, process1 will get a SIGPIPE on the next write. The default action for SIGPIPE is exit. But a program can catch or ignore the signal. Both mechanisms depend on data flowing across the pipe.
 

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UNBUFFER(1)						      General Commands Manual						       UNBUFFER(1)

NAME
unbuffer - unbuffer output SYNOPSIS
unbuffer program [ args ] INTRODUCTION
unbuffer disables the output buffering that occurs when program output is redirected from non-interactive programs. For example, suppose you are watching the output from a fifo by running it through od and then more. od -c /tmp/fifo | more You will not see anything until a full page of output has been produced. You can disable this automatic buffering as follows: unbuffer od -c /tmp/fifo | more Normally, unbuffer does not read from stdin. This simplifies use of unbuffer in some situations. To use unbuffer in a pipeline, use the -p flag. Example: process1 | unbuffer -p process2 | process3 CAVEATS
unbuffer -p may appear to work incorrectly if a process feeding input to unbuffer exits. Consider: process1 | unbuffer -p process2 | process3 If process1 exits, process2 may not yet have finished. It is impossible for unbuffer to know long to wait for process2 and process2 may not ever finish, for example, if it is a filter. For expediency, unbuffer simply exits when it encounters an EOF from either its input or process2. In order to have a version of unbuffer that worked in all situations, an oracle would be necessary. If you want an application-specific solution, workarounds or hand-coded Expect may be more suitable. For example, the following example shows how to allow grep to finish pro- cessing when the cat before it finishes first. Using cat to feed grep would never require unbuffer in real life. It is merely a place- holder for some imaginary process that may or may not finish. Similarly, the final cat at the end of the pipeline is also a placeholder for another process. $ cat /tmp/abcdef.log | grep abc | cat abcdef xxxabc defxxx $ cat /tmp/abcdef.log | unbuffer grep abc | cat $ (cat /tmp/abcdef.log ; sleep 1) | unbuffer grep abc | cat abcdef xxxabc defxxx $ BUGS
The man page is longer than the program. SEE ALSO
"Exploring Expect: A Tcl-Based Toolkit for Automating Interactive Programs" by Don Libes, O'Reilly and Associates, January 1995. AUTHOR
Don Libes, National Institute of Standards and Technology 1 June 1994 UNBUFFER(1)
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