02-01-2005
Yes,
I am doing the same thing.
awk -v a=xyz 'BEGIN{print "before"; print a}{print "during"}END {print "after"}'
This doesn't print the variable a;
But on doing
awk -v a=xyz 'BEGIN{}{print "before"; print a}{print "during"}END {print "after"}'
or
awk -v a=xyz 'BEGIN{print "before"}{print a}{print "during"}END {print "after"}'
i.e. taking variable printing block outside of BEGIN scope it prints.
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NAME
paste - paste multiple files together
SYNOPSIS
paste [-s] [-d list] file...
OPTIONS
-d Set delimiter used to separate columns to list.
-s Print files sequentially, file k on line k.
EXAMPLES
paste file1 file2 # Print file1 in col 1, file2 in col 2
paste -s f1 f2 # Print f1 on line 1 and f2 on line 2
paste -d : file1 file2
# Print the lines separated by a colon
DESCRIPTION
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separated by the delimiters given with the option -s. If no list is given, a tab is substituted for every linefeed, except the last one.
If end-of-file is hit on an input file, subsequent lines are empty. Suppose a set of k files each has one word per line. Then the paste
output will have k columns, with the contents of file j in column j. If the -s flag is given, then the first file is on line 1, the second
file on line 2, etc. In effect, -s turns the output sideways.
If a list of delimiters is given, they are used in turn. The C escape sequences
, , \, and are used for linefeed, tab, backslash,
and the null string, respectively.
PASTE(1)