hi..
this is my question:
it is possible transfer parameters from my program written in C to a .ksh script?
how can i do it?
i have a program in C, what is called from a .ksh script, and i need what the C program returns some values (parameters)
please, help me - any idea
thanks
... (2 Replies)
Hi,
I am looking for a way to utilize password when the ksh program is launched.
What's the standard or best way to do it?
Thanks for your help! (5 Replies)
Hi,
is there problem with grep command when using ksh?
I had the below command:
/usr/bin/grep \""$Mon $NewDD\"" /tmp/timemanager/intlog.$$ >> /tmp/timemanager/log.$$ 2>/dev/null
when I run ksh in debug mode, this command can not grep anything even the data is in the file.
+ /usr/bin/grep... (3 Replies)
I want to get previous date from date command. I am using ksh shell.
Exmp:
today is 2008.09.04
I want the result : 2008.09.03
Please help.
Thanks in advance. (4 Replies)
Hi i am writing a cron job.
so for it i need the 60 days old date form current date in variable.
Like today date is 27 jan 2011 then output value will be stote in variable in formet Nov 27.
i am using EST date, and tried lot of solution and see lot of post but it did not helpful for me. so... (3 Replies)
In KSH, I am pasting 2 almost identical files together and each one has a date and time on each line. I need to determine if the first instance of the date/time is greater than the 2nd instance of the date/time. If the first instance is greater, I just need to echo that line.
I thought I would... (4 Replies)
Hi,
I have a text file with multiple sql statements in which I have pick only the below select update and delete statements and do print as given below.
All the select,update,delete statements will be as same as ( subquery with ().all statements ending with ; ) the examples given below.
1)... (19 Replies)
hi friends,
I m trying to write a script which compares to dates.
for this i am converting dates into no using synatx
as below
v2=`date | awk '{print $2,$3,$4}'`
v3=`date +%s -d "$v2"`
this syntax is working in bash shell ,but fails in ksh shell.
please suggest on this. (12 Replies)
Dear all,
I have an user passing 2 parameter 31/03/2015 and 02/04/2015 to a ksh script. How to print the start date to end date.
Expected output is :
31/03/2015
01/04/2015
02/04/2015
Note :
1. Im using aix and ksh
2. I have tried to convert the given input into a date, didnt... (0 Replies)
Discussion started by: mr.rajaravi
0 Replies
LEARN ABOUT OPENDARWIN
expr
EXPR(1) BSD General Commands Manual EXPR(1)NAME
expr -- evaluate expression
SYNOPSIS
expr expression
DESCRIPTION
The expr utility evaluates expression and writes the result on standard output.
All operators are separate arguments to the expr utility. Characters special to the command interpreter must be escaped.
Operators are listed below in order of increasing precedence. Operators with equal precedence are grouped within { } symbols.
expr1 | expr2
Returns the evaluation of expr1 if it is neither an empty string nor zero; otherwise, returns the evaluation of expr2.
expr1 & expr2
Returns the evaluation of expr1 if neither expression evaluates to an empty string or zero; otherwise, returns zero.
expr1 {=, >, >=, <, <=, !=} expr2
Returns the results of integer comparison if both arguments are integers; otherwise, returns the results of string comparison using
the locale-specific collation sequence. The result of each comparison is 1 if the specified relation is true, or 0 if the relation
is false.
expr1 {+, -} expr2
Returns the results of addition or subtraction of integer-valued arguments.
expr1 {*, /, %} expr2
Returns the results of multiplication, integer division, or remainder of integer-valued arguments.
expr1 : expr2
The ``:'' operator matches expr1 against expr2, which must be a regular expression. The regular expression is anchored to the begin-
ning of the string with an implicit ``^''. expr expects "basic" regular expressions, see re_format(7) for more information on regu-
lar expressions.
If the match succeeds and the pattern contains at least one regular expression subexpression ``(...)'', the string corresponding to
``1'' is returned; otherwise the matching operator returns the number of characters matched. If the match fails and the pattern
contains a regular expression subexpression the null string is returned; otherwise 0.
Parentheses are used for grouping in the usual manner.
EXAMPLES
1. The following example adds one to the variable a.
a=`expr $a + 1`
2. The following example returns the filename portion of a pathname stored in variable a. The // characters act to eliminate ambiguity
with the division operator.
expr //$a : '.*/(.*)'
3. The following example returns the number of characters in variable a.
expr $a : '.*'
DIAGNOSTICS
The expr utility exits with one of the following values:
0 the expression is neither an empty string nor 0.
1 the expression is an empty string or 0.
2 the expression is invalid.
STANDARDS
The expr utility conforms to IEEE Std 1003.2 (``POSIX.2'').
BSD July 3, 1993 BSD