hi..
this is my question:
it is possible transfer parameters from my program written in C to a .ksh script?
how can i do it?
i have a program in C, what is called from a .ksh script, and i need what the C program returns some values (parameters)
please, help me - any idea
thanks
... (2 Replies)
Hi,
I am looking for a way to utilize password when the ksh program is launched.
What's the standard or best way to do it?
Thanks for your help! (5 Replies)
Hi,
is there problem with grep command when using ksh?
I had the below command:
/usr/bin/grep \""$Mon $NewDD\"" /tmp/timemanager/intlog.$$ >> /tmp/timemanager/log.$$ 2>/dev/null
when I run ksh in debug mode, this command can not grep anything even the data is in the file.
+ /usr/bin/grep... (3 Replies)
I want to get previous date from date command. I am using ksh shell.
Exmp:
today is 2008.09.04
I want the result : 2008.09.03
Please help.
Thanks in advance. (4 Replies)
Hi i am writing a cron job.
so for it i need the 60 days old date form current date in variable.
Like today date is 27 jan 2011 then output value will be stote in variable in formet Nov 27.
i am using EST date, and tried lot of solution and see lot of post but it did not helpful for me. so... (3 Replies)
In KSH, I am pasting 2 almost identical files together and each one has a date and time on each line. I need to determine if the first instance of the date/time is greater than the 2nd instance of the date/time. If the first instance is greater, I just need to echo that line.
I thought I would... (4 Replies)
Hi,
I have a text file with multiple sql statements in which I have pick only the below select update and delete statements and do print as given below.
All the select,update,delete statements will be as same as ( subquery with ().all statements ending with ; ) the examples given below.
1)... (19 Replies)
hi friends,
I m trying to write a script which compares to dates.
for this i am converting dates into no using synatx
as below
v2=`date | awk '{print $2,$3,$4}'`
v3=`date +%s -d "$v2"`
this syntax is working in bash shell ,but fails in ksh shell.
please suggest on this. (12 Replies)
Dear all,
I have an user passing 2 parameter 31/03/2015 and 02/04/2015 to a ksh script. How to print the start date to end date.
Expected output is :
31/03/2015
01/04/2015
02/04/2015
Note :
1. Im using aix and ksh
2. I have tried to convert the given input into a date, didnt... (0 Replies)
Discussion started by: mr.rajaravi
0 Replies
LEARN ABOUT SUNOS
expr
expr(1B) SunOS/BSD Compatibility Package Commands expr(1B)NAME
expr - evaluate arguments as a logical, arithmetic, or string expression
SYNOPSIS
/usr/ucb/expr argument...
DESCRIPTION
The expr utility evaluates expressions as specified by its arguments. After evaluation, the result is written on the standard output. Each
token of the expression is a separate argument, so terms of the expression must be separated by blanks. Characters special to the shell
must be escaped. Note: 0 is returned to indicate a zero value, rather than the null string. Strings containing blanks or other special
characters should be quoted. Integer-valued arguments may be preceded by a unary minus sign. Internally, integers are treated as 32-bit,
two's-complement numbers.
The operators and keywords are listed below. Characters that need to be escaped are preceded by `'. The list is in order of increasing
precedence, with equal precedence operators grouped within {} symbols.
expr | expr
Returns the evaluation of the first expr if it is neither NULL nor 0; otherwise, returns the evaluation of the second expr if it is not
NULL; otherwise, 0.
expr & expr
Returns the first expr if neither expr is NULL or 0, otherwise returns 0.
expr { =, , , <, <=, != } expr
Returns the result of an integer comparison if both arguments are integers, otherwise returns the result of a lexical comparison.
expr { +, - } expr
Addition or subtraction of integer-valued arguments.
expr { , /, % } expr
Multiplication, division, or remainder of the integer-valued arguments.
string : regular-expression
match string regular-expression
The two forms of the matching operator above are synonymous. The matching operators : and match compare the first argument with the
second argument which must be a regular expression. Regular expression syntax is the same as that of regexp(5), except that all pat-
terns are "anchored" (treated as if they begin with ^) and therefore ^ is not a special character, in that context. Normally, the
matching operator returns the number of characters matched (0 on failure). Alternatively, the ... pattern symbols can be used to
return a portion of the first argument.
substr string integer-1 integer-2
Extracts the substring of string starting at position integer-1 and of length integer-2 characters. If integer-1 has a value greater
than the length of string, expr returns a null string. If you try to extract more characters than there are in string, expr returns all
the remaining characters from string. Beware of using negative values for either integer-1 or integer-2 as expr tends to run forever
in these cases.
index string character-list
Reports the first position in string at which any one of the characters in character-list matches a character in string.
length string
Returns the length (that is, the number of characters) of string.
( expr )
Parentheses may be used for grouping.
EXAMPLES
Example 1: Adding an integer to a shell variable
Add 1 to the shell variable a.
a='expr $a + 1'
Example 2: Returning a path name segment
Return the last segment of a path name (that is, the filename part). Watch out for / alone as an argument: expr will take it as the divi-
sion operator (see BUGS below).
# 'For $a equal to either "/usr/abc/file" or just "file"'
expr $a : '.*/ $a
Example 3: Using // characters to simplify the expression
The addition of the // characters eliminates any ambiguity about the division operator and simplifies the whole expression.
# A better representation of example 2.
expr //$a : '.*/
Example 4: Returning the value of a variable
Returns the number of characters in $VAR.
expr $VAR : '.*'
EXIT STATUS
expr returns the following exit codes:
0 If the expression is neither NULL nor 0.
1 If the expression is NULL or 0.
2 For invalid expressions.
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWscpu |
+-----------------------------+-----------------------------+
SEE ALSO sh(1), test(1), attributes(5), regexp(5)DIAGNOSTICS
syntax error for operator/operand errors
non-numeric argument if arithmetic is attempted on such a string
division by zero if an attempt to divide by zero is made
BUGS
After argument processing by the shell, expr cannot tell the difference between an operator and an operand except by the value. If $a is an
=, the command:
expr $a = '='
looks like:
expr = = =
as the arguments are passed to expr (and they will all be taken as the = operator). The following works:
expr X$a = X=
Note: the match, substr, length, and index operators cannot themselves be used as ordinary strings. That is, the expression:
example% expr index expurgatorious length
syntax error
example%
generates the `syntax error' message as shown instead of the value 1 as you might expect.
SunOS 5.10 6 Jun 2000 expr(1B)