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Top Forums UNIX for Advanced & Expert Users Getting sysdate - 2 by an unix command Post 5966 by LivinFree on Monday 27th of August 2001 11:53:57 PM
Old 08-28-2001

Here is one way:


#!/usr/bin/sh
_day=`date +%d`
_month=`date +%m`
_year=`date +%y`
newday=`expr $_day - 2`
echo "Two days ago was $_month/$newday/$_year "


I know the GNU date provides an easier way, but this is more portable...

your to_char function is up to you :P
 

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DATETIME.FORMAT(3)							 1							DATETIME.FORMAT(3)

DateTime::format - Returns date formatted according to given format

       Object oriented style

SYNOPSIS
public string DateTime::format (string $format) DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format) Procedural style string date_format (DateTimeInterface $object, string $format) Returns date formatted according to given format. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3) o $format - Format accepted by date(3). RETURN VALUES
Returns the formatted date string on success or FALSE on failure. EXAMPLES
Example #1 DateTime.format(3) example Object oriented style <?php $date = new DateTime('2000-01-01'); echo $date->format('Y-m-d H:i:s'); ?> Procedural style <?php $date = date_create('2000-01-01'); echo date_format($date, 'Y-m-d H:i:s'); ?> The above example will output: 2000-01-01 00:00:00 NOTES
This method does not use locales. All output is in English. SEE ALSO
date(3). PHP Documentation Group DATETIME.FORMAT(3)
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