Sponsored Content
Top Forums Shell Programming and Scripting Command output to a variable. Post 59269 by zazzybob on Wednesday 15th of December 2004 05:13:42 AM
Old 12-15-2004
I know that that kind of redirection will work, but it's unneccessary - you can just take the filename onto the end of the command.

Cheers
ZB
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Assigning output of command to a variable

Hi, I'm trying to assign the output of a command to a variable and then concat it with another string, however, it keeps overwriting the original string instead of adding on to the end of the string. Contents of test.txt --> This is a test var1="`head -n 1 test.txt`" echo $var1 (This is a... (5 Replies)
Discussion started by: oma04
5 Replies

2. UNIX for Dummies Questions & Answers

ls command output to variable in script

Hi, I wrote a script to get the oldest file from a directory path (which is passed as a parameter to the script) ######################################################### XMLFILE_PATH={$1} cd $XMLFILE_PATH JPM_FILENAME = `(ls -tr User* | head -1)` #echo $JPM_FILENAME ###### END... (1 Reply)
Discussion started by: dsrookie
1 Replies

3. Shell Programming and Scripting

get characters from output of a command in a variable

Hi, i have two questions, I am new to programming 1. I have an output of a command and i want to get some specific part of it in a variable. i am trying sr=`some comand xyz| grep 'Last Changed Rev:' | cut -c19-` now variable sr gets a end of line character at end. output of the command... (3 Replies)
Discussion started by: muaz
3 Replies

4. Shell Programming and Scripting

Assigning output of a command to variable

When I run time -p <command>, it outputs: real X.XX user X.XX sys X.XXwhere X.XX is seconds. How I can take just that first number output, the seconds of real time, and assign that to a variable? (9 Replies)
Discussion started by: jeriryan87
9 Replies

5. UNIX for Dummies Questions & Answers

saving command output to a variable

Hello, I have a shell script containing a command string in the following format: command1 | command2 | cut -c9-16 The output from this is a record number (using characters 9-16 of the original output string) e.g. ORD-1234 I wish to save this value to a variable for use in later commands... (4 Replies)
Discussion started by: philjo
4 Replies

6. Programming

Command output into a variable

Hi, with this command: cu -l /dev/ttyACM0 -s 9600 > name.txt I put the output of the port in a txt Is posible to do the same (or similar) in a var directly, inside a C program? cu -l /dev/ttyACM0 -s 9600 > variable ? I have trying this withs pipes, but i dont know how to... (6 Replies)
Discussion started by: daaran
6 Replies

7. Shell Programming and Scripting

set variable to command output

I'm hoping you guys can help me out here. I've been trying different methods to try and get what IW as hoping would be a fairly simple script but has turned into a pain. Bit of background - I am writing a script to check values in certain failes to ensure they are corerct. I'm runnign this on... (2 Replies)
Discussion started by: stuc
2 Replies

8. UNIX for Advanced & Expert Users

ls output into a read command as a variable

I'm working on a short BASH script on my Ubuntu box that will run powerpoint scripts with MS Powerpoint Viewer 2007 via WINE. I can run the presentation when I run it manually but what i'd like to do is have the script look for the newest file then run it. #! /bin/sh # Start the newest... (2 Replies)
Discussion started by: binary-ninja
2 Replies

9. Shell Programming and Scripting

Output of find command to variable?

Hi, I'd like to assign the output of the find command to a variable. What I need is to run the find command, and if it returns zero files, the program exits. so i'm trying to assign the output of the find command to the $var1 variable....and then if this is less than one, I echo a... (2 Replies)
Discussion started by: horhif
2 Replies

10. Shell Programming and Scripting

How to get the output of a ISQL command in a variable?

I am trying to run a query which returns a sum value(a number). I want to get it in a variable so that i can refer to that variable in different places. when i am running the following command variable=`isql -Uuser -Sserver -Ppassword 1> select sum(count(*)) from xyz..abc where clm_id... (2 Replies)
Discussion started by: Sharma331
2 Replies
GOPEN(1)						       GNUstep System Manual							  GOPEN(1)

NAME
gopen - open files SYNOPSIS
gopen [-a application] [-o] [-p] [-NXHost hostname] [filename] DESCRIPTION
The gopen command allows you open a file (or directory) as if you had double clicked the object's icon. It is possible to specify one or more filenames which are interpreted relative to the current working directory. By default, gopen will open filename with the application currently assigned to the file's extension. But by specifing the -a flag on the command line you can tell gopen to open the file with another application. You can also directly print a file without ( -p ) or with ( -p -o ) opening it. As with most other GNUstep software, it is easily possible to attach the process to a remote window server using the -NXHost flag. OPTIONS
-a application use application to open filename -o open filename (may be used in conjunction with -p ). -p print filename instead of opening. -NXHost hostname attach to remote window server on hostname EXAMPLES
Open all files with a .txt extension in the current directory: gopen *.txt To open a source file in CodeEditor (instead of the current default application), type: gopen -a CodeEditor MySourceFile.m To print the .plan file in your home folder, use the -p flag: gopen -p ~/.plan BUGS
Using the -a application argument, gopen allows you to open any kind of file with any application you want. This does, however, not work with applications employing the NSDocument architecture as they will only receive filenames whose types the application has registered. To circumvent this limitation, applications may advertise their ability to open all kinds of files through the "*" filetype. When gopen is used with only the -a application argument but no filename present, the application is simply launched without opening a specific file. SEE ALSO
GNUstep(7), openapp(1) HISTORY
gopen was written November 2001. This manual page was first written July 2003. AUTHORS
gopen was written by Gregory Casamento <greg_casamento@yahoo.com>. This man page was written by Martin Brecher <martin@mb-itconsulting.com>. GNUstep August 2003 GOPEN(1)
All times are GMT -4. The time now is 10:21 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy