Sponsored Content
Full Discussion: user list
Top Forums UNIX for Advanced & Expert Users user list Post 58809 by whatisthis on Thursday 2nd of December 2004 12:03:52 PM
Old 12-02-2004
user list

Hi,
I have root access on Linux red hat server.
How do I see the current user list and group they belong?

ThankS!
 

10 More Discussions You Might Find Interesting

1. AIX

list of default umask by user

Hi, Do you know if it's possible to have the user list with their umask on AIX system ? I need to check if they are OK but with smit and user by user, it will take all the day. :) An idea ? Thx a lot. (3 Replies)
Discussion started by: Zlikos
3 Replies

2. Shell Programming and Scripting

How to process the user id list in /etc/group?

To all, I need to find a group in /etc/group and if found, I need to list out all the login ids for that group - one login id per line. To find the list of user login ids for group X, I probably will use cat /etc/group|grep ^X:|cut -d: -f4 This will return back a list of comma delimited... (4 Replies)
Discussion started by: april
4 Replies

3. Shell Programming and Scripting

IF $USER is not in this list of users, then do this

I need to add to a BASH script if ${USER} is not in a list of users (smitha, brownd, adamsp) then do something... what is the best shortest way to accomplish an if statement with a list like this? Also the list of users should be in the script, not an external file. Thanks! (5 Replies)
Discussion started by: glev2005
5 Replies

4. Shell Programming and Scripting

How to get list of user into an array..

Hi, cut -d: -f1,3 /etc/group >rpt.out I have a doubt in above unix commands. right i am getting list of group user id into rpt.out file. instead i need to store it as an array. could you please tell me how can i get list of user into an array.. If u could tell me give me in perl script... (2 Replies)
Discussion started by: solo123
2 Replies

5. Shell Programming and Scripting

Write a scripts to kill idle user for 60 min. & email user list to admin in text file

Folks, I have written one script for following condition by referring some of online post in this forum. Please correct it if I'm missing something in it. (OS: AIX 5.3) List the idle user. (I used whoidle command to list first 15 user and get username, idle time, pid and login time).... (4 Replies)
Discussion started by: sumit30
4 Replies

6. Solaris

Solaris command to list user

Can someone tell me the Solaris equivelant of aix command lsuser? I need to find a users primary and secondary group. I don't have smit... (2 Replies)
Discussion started by: Grueben
2 Replies

7. UNIX for Advanced & Expert Users

How to get User list from different groups and root?

Hi all, I want to list out users from different group and root, who are roaming in our group or root as a user. how can i list out this users ? (1 Reply)
Discussion started by: kpatel97
1 Replies

8. Shell Programming and Scripting

List of process of user

Hi, I need an output of process running on server, i am executing ps -ef | grep test output is asak 22362 1 0 Nov07 ? 00:00:03 /usr/software/bin/perl-5.8.8 /u/assk/bin/test -v none JOBID=2012117 asak 23748 22362 0 Nov07 ? 00:00:00 /usr/software/bin/perl-5.8.8... (3 Replies)
Discussion started by: asak
3 Replies

9. Emergency UNIX and Linux Support

A way to capture the user list

Can someone please help me with a way to generate a user list on a system along with the group to which the id belongs? (8 Replies)
Discussion started by: ggayathri
8 Replies

10. Shell Programming and Scripting

Active User List Script

Hello guys ! I tried a script to list all the active users in the current server in AIX who | grep '^user' this displays the entire line ... All I need is only the user list I found a command for linux using grep -o word grep -o was not recognized in AIX Can you guys help me out ? Use... (2 Replies)
Discussion started by: varun aravinth
2 Replies
PAM_WHEEL(8)							 Linux-PAM Manual						      PAM_WHEEL(8)

NAME
pam_wheel - Only permit root access to members of group wheel SYNOPSIS
pam_wheel.so [debug] [deny] [group=name] [root_only] [trust] [use_uid] DESCRIPTION
The pam_wheel PAM module is used to enforce the so-called wheel group. By default it permits root access to the system if the applicant user is a member of the wheel group. If no group with this name exist, the module is using the group with the group-ID 0. OPTIONS
debug Print debug information. deny Reverse the sense of the auth operation: if the user is trying to get UID 0 access and is a member of the wheel group (or the group of the group option), deny access. Conversely, if the user is not in the group, return PAM_IGNORE (unless trust was also specified, in which case we return PAM_SUCCESS). group=name Instead of checking the wheel or GID 0 groups, use the name group to perform the authentication. root_only The check for wheel membership is done only. trust The pam_wheel module will return PAM_SUCCESS instead of PAM_IGNORE if the user is a member of the wheel group (thus with a little play stacking the modules the wheel members may be able to su to root without being prompted for a passwd). use_uid The check for wheel membership will be done against the current uid instead of the original one (useful when jumping with su from one account to another for example). MODULE TYPES PROVIDED
The auth and account module types are provided. RETURN VALUES
PAM_AUTH_ERR Authentication failure. PAM_BUF_ERR Memory buffer error. PAM_IGNORE The return value should be ignored by PAM dispatch. PAM_PERM_DENY Permission denied. PAM_SERVICE_ERR Cannot determine the user name. PAM_SUCCESS Success. PAM_USER_UNKNOWN User not known. EXAMPLES
The root account gains access by default (rootok), only wheel members can become root (wheel) but Unix authenticate non-root applicants. su auth sufficient pam_rootok.so su auth required pam_wheel.so su auth required pam_unix.so SEE ALSO
pam.conf(5), pam.d(5), pam(8) AUTHOR
pam_wheel was written by Cristian Gafton <gafton@redhat.com>. Linux-PAM Manual 09/19/2013 PAM_WHEEL(8)
All times are GMT -4. The time now is 01:40 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy