Hi
I would like to know wheather there is anyway to pass a variable to grep argument like this
grep "$myvar" $myfile
i would put this in a function and then call this function by setting different values to myvar and myfile.
is this possible at all.
regards
Hrishy (4 Replies)
I have a large file that I am grepping to find a certain string.
grep 'C:\Data\Directory\Test.txt' test.txt
It can not find it even though I know it is in there . I know that there is a problem with the backslashes but I can't get it to work. I tried
grep... (2 Replies)
Hi there, this is a very simple question.
When I do grep -c "PWD" filename, I get 5. This means the filename contains 5 lines of "PWD" occurence.
I tried to assign to a variable. int= grep -c "PWD" filename
When I typed echo $int
The output:
5
I get an empty line space. Now I... (1 Reply)
I have a problem. Suppose I have a log named transport.log
>>
tp finished with return code: 203
meaning:
wrong syntax in tp call
....
tp finished with return code: 0
meaning:
Everything ok.
<<
What i want to do is to get the return code of the 1st one. So I would probably do:... (2 Replies)
Changed Problem its a sed actually...
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
Use a sed command to create an output file from the input file. The input... (2 Replies)
Hi,
When i try this it is not executing either result or total, pls can any one help me in this.
max=month_134.log
grep result|total $max > log.txt
In month_134.log, it should contain either result or total and then send it to log.txt.It should execute result or total in log.txt
... (3 Replies)
Hi
I am trying to grep a string in a directory which is having 5000 files.
PA>> grep -iH 'linc.unisure_pr13n' *
bash: /usr/bin/grep: Arg list too long
I am getting the error. i also tried
PA>> ls -ltr | grep -iH 'linc.unisure_pr13n' *
but still i am getting the error
Please Advice... (4 Replies)
Hi everyone
i am facing a strange problem in grep below is the code
RC=0
grep $ERROR_MASK $LOG_FILE 2>&1 > /dev/null && RC=1 || RC=0
what does the above statment do i mean it search for error mask into log file and redirect the error to console null then what's the meaning of RC=1 ||... (2 Replies)
Hello. I'm learning shell scripting right now and I'm trying simple scripts. I have a problem with the one below. The idea is to found the number of files containing asd in their name. Here's the code:
#!/bin/sh
pattern=asd
total=0
for f in *
do
&& continue
if grep $pattern $f >... (3 Replies)
I don't know if you guys get this problem sometimes at Terminal but I had been having this problem since yesterday :( Maybe I overdid the Terminal. Even the codes that used to work doesn't work anymore.
Here is what 's happening:
* I wanted to remove lines containing digits so I used this... (25 Replies)
Discussion started by: Nexeu
25 Replies
LEARN ABOUT LINUX
zegrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)