Hi All,
Today I got a small problem while handling zipped files in PROD support.
There are files in this format and I had to grep them reading some contents
A.B.gz.C.D
where A,B,C and D stand for variables (like FIRST.NAME.gz.MIDDLE.LAST).
I know that these files are zipped files and If I... (1 Reply)
directory name = /usr/tom/1997
files -
ABC_1997_ST1_BCD.SQL
BCD_1997_ST1_EFG_SAB.SQL
TTT_EBC_1997_ST1_A.SQL
sub directory - /usr/tom/1997/jan
a) I want to just rename the all files ending with '.SQL' and also its contents in the 1997 directory(excluding subdirectories eg... (3 Replies)
Hello!
I am not familiar with UNIX and I have this problem:
I need to move files from a UNIX machine to a PC. UNIX file names contain ":" as special character which is not recognized in a PC.
How can I change ":" for "_" in the name of a bunch of files in UNIX?
Thanks for your help. (7 Replies)
I have a list of files named ab_*.csv
I would like to remane them all by removing the ab_ and have *.csv
I did the following but I am surely missing something.
/* wrong script */
for i in `ls -1 ab_*`; do mv ab_$i $i; done
Thanks in advance. (1 Reply)
Hi all,
using a utility image file was named starting with blank space and a blank space in between. I want to rename the files.
file names are in the format " sb 12.tif"," sb 13.tif"," sb 14.tif" the files are in thousands. i want to rename as 12.tif, 13.tif, 14.tif....
thanks. (3 Replies)
Hi All
I have a folder that contains hundreds of file with a names
3.msa
4.msa
21.msa
6.msa
345.msa
456.msa
98.msa
...
...
...
I need rename each of this file by adding "core_" in the begiining of each file such as
core_3.msa
core_4.msa
core_21.msa (4 Replies)
Hi,
I have a list of files in a folder with the same name ending (over 1000 files)
joe.jpy.jpeg
joe1.jpy.jpeg
joe2.jpy.jpeg
jon3.jpy.jpeg
jor5.jpy.jpeg
.....jpy.jpeg
etc.
I want to change jpy to hhk
So the output will be:
joe.hhk.jpeg
joe1.hhk.jpeg
joe2.hhk.jpeg
jon3.hhk.jpeg... (3 Replies)
Hi
i have to achieve the following
i have files as xyz001.csv, xyz002.csv.......xyz0025.csv in a folder, i need to keep xyz001.csv as it is
but want to remove the extra zero on filename from 10 say
xyz0010 should be renamed to xyz010
xyz0025 should be renamed as xyz025
Note xyz... (8 Replies)
Hello,
I am looking for a command line that will rename name files :
f700_abc_o_t_MASTERID_AS_AE_20130323.csv
like this
f700_abc_o_t_MASTERID_AS_AE_20130324.csv
The great idea could be to get the date stamp 20130323
and change any part of it, instead of just change the... (4 Replies)
Hi,
In sftp script to get files, I have to rename all the files which I am picking. Rename command does not work here. Is there any way to do this?
I am using #!/bin/ksh
For eg: sftp user@host <<EOF
cd /path
get *.txt
rename *.txt *.txt.done
... (7 Replies)
Discussion started by: jhilmil
7 Replies
LEARN ABOUT ULTRIX
expr
expr(1) General Commands Manual expr(1)Name
expr - evaluate expressions
Syntax
expr arg...
Description
The arguments are taken as an expression. After evaluation, the result is written on the standard output. Each token of the expression is
a separate argument.
The operators and keywords are listed below. The list is in order of increasing precedence, with equal precedence operators grouped.
expr | expr Yields the first expr if it is neither null nor 0. Otherwise yields the second expr.
expr & expr Yields the first expr if neither expr is null or 0. Otherwise yields 0.
expr relop expr The relop is one of < <= = != >= > and yields 1 if the indicated comparison is true, '0' if false. The comparison is
numeric if both expr are integers, otherwise lexicographic.
expr + expr
expr - expr
Yields addition or subtraction of the arguments.
expr * expr
expr / expr
expr % expr
Yields multiplication, division, or remainder of the arguments.
expr : expr The matching operator compares the string first argument with the regular expression second argument; regular expres-
sion syntax is the same as that of The (...) pattern symbols can be used to select a portion of the first argument.
Otherwise, the matching operator yields the number of characters matched ('0' on failure).
( expr ) parentheses for grouping.
Examples
The first example adds 1 to the Shell variable a:
a=`expr $a + 1`
The second example finds the file name part (least significant part) of the pathname stored in variable a,
expr $a : '.*/(.*)' '|' $a
Note the quoted Shell metacharacters.
Diagnostics
The command returns the following exit codes:
0 The expression is neither null nor '0'.
1 The expression is null or '0'.
2 The expression is invalid.
See Alsoed(1), sh(1), test(1)expr(1)