variable passed to awk Post: 55599

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variable passed to awk

Does anybody know how to print a variable passed to awk command? awk -F"|" 'BEGIN {print $job,"\n","Question \n"} {print $1,$2$4," ",$3}' "job=$job1" file1 I am trying to pass job the variable job1. the output is blank. ??

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optisa

optisa(1)                                                          User Commands                                                         optisa(1)

NAME

       optisa - determine which variant instruction set is optimal to use

SYNOPSIS

       optisa instruction_set...

DESCRIPTION

       optisa  prints  which  instruction_set out of the ones specified in the command will perform best on  this machine.  In this case, ``best''
       is defined by the order  in which instruction set names are returned by  isalist(1). Possible  values  for  instruction_set  are  given  in
       isalist(5).

ATTRIBUTES

       See attributes(5) for descriptions of the following attributes:

       +-----------------------------+-----------------------------+
       |      ATTRIBUTE TYPE         |      ATTRIBUTE VALUE        |
       +-----------------------------+-----------------------------+
       |Availability                 |SUNWcsu                      |
       +-----------------------------+-----------------------------+

EXIT STATUS

       The following exit values are returned:

       0        One of the  instruction_set values you specified is printed by this command.

       1        There is no output; that is, this machine cannot use any  instruction_set that you specified with the optisa command.

SEE ALSO

       isalist(1), uname(1), attributes(5), isalist(5)

NOTES

       optisa is preferable to  uname -p or  uname -m (see uname(1)) in determining which of several binary versions of a given program  should be
       used on the given machine.

SunOS 5.10                                                          25 Jul 1997                                                          optisa(1)

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