06-24-2004
Can't figure out how to display specific data from a line using awk.
Hello,
I cannot figure this one out. I would like to do the following. I have a line that has 7 words. It is possible that the line can have 20 words too. I always want to show the 9th word and beyond. The 9th word will always change so I do not have something to search for, so I think the best option is to use awk. I know the '^' character is for beginning of line, and '$' is for end of line. So far I have figured out his much...
cat {file} |awk '{print $9}'
I don't know how to code 9th word and 'to the end of line'.
Help is greatly appreciated,
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LEARN ABOUT DEBIAN
sql::reservedwords::postgresql
SQL::ReservedWords::PostgreSQL(3pm) User Contributed Perl Documentation SQL::ReservedWords::PostgreSQL(3pm)
NAME
SQL::ReservedWords::PostgreSQL - Reserved SQL words by PostgreSQL
SYNOPSIS
if ( SQL::ReservedWords::PostgreSQL->is_reserved( $word ) ) {
print "$word is a reserved PostgreSQL word!";
}
DESCRIPTION
Determine if words are reserved by PostgreSQL.
METHODS
is_reserved( $word )
Returns a boolean indicating if $word is reserved by either PostgreSQL 7.3, 7.4, 8.0 or 8.1.
is_reserved_by_postgresql7( $word )
Returns a boolean indicating if $word is reserved by either PostgreSQL 7.3 or 7.4.
is_reserved_by_postgresql8( $word )
Returns a boolean indicating if $word is reserved by either PostgreSQL 8.0 or 8.1.
reserved_by( $word )
Returns a list with PostgreSQL versions that reserves $word.
words
Returns a list with all reserved words.
EXPORTS
Nothing by default. Following subroutines can be exported:
is_reserved
is_reserved_by_postgresql7
is_reserved_by_postgresql8
reserved_by
words
SEE ALSO
SQL::ReservedWords
<http://www.postgresql.org/docs/manuals/>
AUTHOR
Christian Hansen "chansen@cpan.org"
COPYRIGHT
This program is free software, you can redistribute it and/or modify it under the same terms as Perl itself.
perl v5.8.8 2008-03-28 SQL::ReservedWords::PostgreSQL(3pm)