02-13-2004
Need Help with KornShell script
I need a KornShell script that will, among all the users currently logged on to the system, find a slot of one hour that contains the most number of users. I know how to list all the users currently logged on but how do I do anything with the times that are listed? Please help, thanks.
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rwho(1) User Commands rwho(1)
NAME
rwho - who is logged in on local machines
SYNOPSIS
rwho [-a]
DESCRIPTION
The rwho command produces output similar to who(1), but for all machines on your network. If no report has been received from a machine
for 5 minutes, rwho assumes the machine is down, and does not report users last known to be logged into that machine.
If a user has not typed to the system for a minute or more, rwho reports this idle time. If a user has not typed to the system for an hour
or more, the user is omitted from the output of rwho unless the -a flag is given.
OPTIONS
-a Report all users whether or not they have typed to the system in the past hour.
FILES
/var/spool/rwho/whod.* information about other machines
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
|Availability |SUNWrcmds |
+-----------------------------+-----------------------------+
SEE ALSO
finger(1), ruptime(1), who(1), in.rwhod(1M), attributes(5)
NOTES
rwho does not work through gateways.
The directory /var/spool/rwho must exist on the host from which rwho is run.
This service takes up progressively more network bandwith as the number of hosts on the local net increases. For large networks, the cost
becomes prohibitive.
The rwho service daemon, in.rwhod(1M), must be enabled for this command to return useful results.
SunOS 5.10 6 Nov 2000 rwho(1)