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Full Discussion: pass variable to awk
Top Forums UNIX for Dummies Questions & Answers pass variable to awk Post 47448 by inquirer on Tuesday 10th of February 2004 11:43:13 PM
Old 02-11-2004
PHP sorry but not working
actually this is a sample of what i want to do:

from the sample code:

Code:
grep "keyword" filename | awk '{print $2}' >> outfile
grep "keyword" filename | awk '{print $3}' >> outfile
        .
        .
        .
grep "keyword" filename | awk '{print $32}' >> outfile

i want to shorten it to loop like this:
Code:
let x = 2

until test $x > 32
do

grep "keyword" filename | awk ...???

let x = x + 1

done

so you see i want to pass a variable to awk where the value will also be the variable for print.

thanks a lot
 

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LEARN ABOUT PLAN9

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
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