Sponsored Content
Full Discussion: Regular Expression
Top Forums UNIX for Dummies Questions & Answers Regular Expression Post 44342 by tikual on Thursday 4th of December 2003 01:52:17 PM
Old 12-04-2003
ok, got your meaning now.

try it
s/\(^.*\~\) *$/\1/
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Regular Expression + Aritmetical Expression

Is it possible to combine a regular expression with a aritmetical expression? For example, taking a 8-numbers caracter sequece and casting each output of a grep, comparing to a constant. THX! (2 Replies)
Discussion started by: Z0mby
2 Replies

2. Programming

What does the regular expression ['(^[^~]+~).*'] mean?

What does the regular expression +~).*'] mean while using it with regexec.When the string "RCHNUSNT35C~rs07/ASM-RS07" is used with the regular expression +~).*'] regexec gives an error. I know what regexec does,but i do not understand what this expression means wrt to this string... any help... (2 Replies)
Discussion started by: anupamar
2 Replies

3. Linux

Regular expression to extract "y" from "abc/x.y.z" .... i need regular expression

Regular expression to extract "y" from "abc/x.y.z" (2 Replies)
Discussion started by: rag84dec
2 Replies

4. UNIX for Dummies Questions & Answers

ls with regular expression

I currently list and sort all the files in a directory which begin with an Upper Case C and end with the extension '#finished#'. Here is the command I use: ls -tr $currentDir/*.#finished# what i need to do now is list all the files in a directory that begin with upper case C and end... (3 Replies)
Discussion started by: rkgudde
3 Replies

5. Shell Programming and Scripting

Integer expression expected: with regular expression

CA_RELEASE has a value of 6. I need to check if that this is a numeric value. if not error. source $CA_VERSION_DATA if * ] then echo "CA_RELESE $CA_RELEASE is invalid" exit -1 fi + source /etc/ncgl/ca_version_data ++ CA_PRODUCT_ID=samxts ++ CA_RELEASE=6 ++ CA_WEEK_NO=7 ++... (3 Replies)
Discussion started by: ketkee1985
3 Replies

6. Programming

Perl: How to read from a file, do regular expression and then replace the found regular expression

Hi all, How am I read a file, find the match regular expression and overwrite to the same files. open DESTINATION_FILE, "<tmptravl.dat" or die "tmptravl.dat"; open NEW_DESTINATION_FILE, ">new_tmptravl.dat" or die "new_tmptravl.dat"; while (<DESTINATION_FILE>) { # print... (1 Reply)
Discussion started by: jessy83
1 Replies

7. UNIX for Advanced & Expert Users

sed: -e expression #1, char 0: no previous regular expression

Hello All, I'm trying to extract the lines between two consecutive elements of an array from a file. My array looks like: problem_arr=(PRS111 PRS213 PRS234) j=0 while } ] do k=`expr $j + 1` sed -n "/${problem_arr}/,/${problem_arr}/p" problemid.txt ---some operation goes... (11 Replies)
Discussion started by: InduInduIndu
11 Replies

8. UNIX for Dummies Questions & Answers

Regular expression help

Hi, I am quite knew to scripting and I am trying to get a regular expression to work to check that a user enters a valid version number such as 1 or 1.1 or 12.3 etc. I dont seem to be able to get it to work as it picks up versions such as 1.......2. I only want it to work with a single dot.... (12 Replies)
Discussion started by: frodo61
12 Replies

9. Shell Programming and Scripting

Regular expression

Can someone please explain me what does this mean? ^{1,50}$ (1 Reply)
Discussion started by: Anupam_Halder
1 Replies

10. Shell Programming and Scripting

Regular expression

I would like to extract "JDBC Thin Client" from (PROGRAM=JDBC Thin Client); and "C:\Python26\python.exe" from (PROGRAM=C:\Python26\python.exe); "txm_v_awsrf_db.pr" from (PROGRAM=txm_v_awsrf_db.pr). if input line like "(PROGRAM=)", it return unknown. Would you help suggest a regular... (4 Replies)
Discussion started by: cstsang
4 Replies
DateTime::Format::Builder::Parser::Dispatch(3pm)	User Contributed Perl Documentation	  DateTime::Format::Builder::Parser::Dispatch(3pm)

NAME
DateTime::Format::Builder::Parser::Dispatch - Dispatch parsers by group SYNOPSIS
package SampleDispatch; use DateTime::Format::Builder ( parsers => { parse_datetime => [ { Dispatch => sub { return 'fnerk'; } } ] }, groups => { fnerk => [ { regex => qr/^(d{4})(dd)(dd)$/, params => [qw( year month day )], }, ] } ); DESCRIPTION
"Dispatch" adds another parser type to "Builder" permitting dispatch of parsing according to group names. SPECIFICATION
"Dispatch" has just one key: "Dispatch". The value should be a reference to a subroutine that returns one of: o "undef", meaning no groups could be found. o An empty list, meaning no groups could be found. o A single string, meaning: use this group o A list of strings, meaning: use these groups in this order. Groups are specified much like the example in the SYNOPSIS. They follow the same format as when you specify them for methods. SIDEEFFECTS
Your group parser can also be a Dispatch parser. Thus you could potentially end up with an infinitely recursive parser. THANKS
See the main module's section. SUPPORT
Support for this module is provided via the datetime@perl.org email list. See http://lists.perl.org/ for more details. Alternatively, log them via the CPAN RT system via the web or email: http://perl.dellah.org/rt/dtbuilder bug-datetime-format-builder@rt.cpan.org This makes it much easier for me to track things and thus means your problem is less likely to be neglected. LICENCE AND COPYRIGHT
Copyright X Iain Truskett, 2003. All rights reserved. This library is free software; you can redistribute it and/or modify it under the same terms as Perl itself, either Perl version 5.000 or, at your option, any later version of Perl 5 you may have available. The full text of the licences can be found in the Artistic and COPYING files included with this module, or in perlartistic and perlgpl as supplied with Perl 5.8.1 and later. AUTHOR
Iain Truskett <spoon@cpan.org> SEE ALSO
"datetime@perl.org" mailing list. http://datetime.perl.org/ perl, DateTime, DateTime::Format::Builder perl v5.10.1 2010-03-14 DateTime::Format::Builder::Parser::Dispatch(3pm)
All times are GMT -4. The time now is 06:53 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy