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Full Discussion: awk printf problem
Top Forums UNIX for Advanced & Expert Users awk printf problem Post 43271 by Perderabo on Friday 14th of November 2003 08:12:57 AM
Old 11-14-2003
It can handle 308 digits. What you're looking for is a guarantee of n digits of integer-like arithmetic accuracy. Floating point arithmetic doesn't behave like that. Don't try to squeeze integer arithmetic behavior out of floating point. If you need integer arithmetic, simply switch to integer arithmetic. You already have the solution to your problem: use bc.

There probably is some number of digits of integer arithmetic style accuracy to had from floating point if you limit yourself to the addition of positive integers (something you were not doing). I don't know what that limit is. Nor do I care. But as soon as you start doing stuff like 9999.9999 you leave floating point behind very quickly. Not all decimal rationals can even be represented in floating point.
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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