08-29-2003
pwd: A specified flag is not valid for this command.
Probably a very straight forward question but please be easy on me, I am v. new to UNIX!
A script that I have runs the line
tmp=`pwd -H`
It works fine, but I needed to make a couple of other changes to the script, nowhere near this line but now this line reports:
pwd: A specified flag is not valid for this command.
When I use the original script again there is no problem at all.
Any ideas as to what may be causing this.
Cheers
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PWD(1) BSD General Commands Manual PWD(1)
NAME
pwd -- return working directory name
SYNOPSIS
pwd [-L | -P]
DESCRIPTION
The pwd utility writes the absolute pathname of the current working directory to the standard output.
Some shells may provide a builtin pwd command which is similar or identical to this utility. Consult the builtin(1) manual page.
The options are as follows:
-L Display the logical current working directory.
-P Display the physical current working directory (all symbolic links resolved).
If no options are specified, the -P option is assumed.
ENVIRONMENT
Environment variables used by pwd:
PWD Logical current working directory.
EXIT STATUS
The pwd utility exits 0 on success, and >0 if an error occurs.
SEE ALSO
builtin(1), cd(1), csh(1), sh(1), getcwd(3)
STANDARDS
The pwd utility conforms to IEEE Std 1003.1-2001 (``POSIX.1'').
BUGS
In csh(1) the command dirs is always faster because it is built into that shell. However, it can give a different answer in the rare case
that the current directory or a containing directory was moved after the shell descended into it.
The -L option does not work unless the PWD environment variable is exported by the shell.
BSD
April 12, 2003 BSD