Sponsored Content
Full Discussion: using variable in a variable
Top Forums Shell Programming and Scripting using variable in a variable Post 38682 by s93366 on Wednesday 23rd of July 2003 09:20:34 AM
Old 07-23-2003
Hi,
Im not following ...
Could you please try and explain more?

thanks

/peter
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

ksh: A part of variable A's name is inside of variable B, how to update A?

This is what I tried: vara=${varb}_count (( vara += 1 )) Thanks for help (4 Replies)
Discussion started by: pa3be
4 Replies

2. Shell Programming and Scripting

Sed variable substitution when variable constructed of a directory path

Hello, i have another sed question.. I'm trying to do variable substition with sed and i'm running into a problem. my var1 is a string constructed like this: filename1 filerev1 filepath1 my var2 is another string constructed like this: filename2 filerev2 filepath2 when i do... (2 Replies)
Discussion started by: alrinno
2 Replies

3. Shell Programming and Scripting

Insert a line including Variable & Carriage Return / sed command as Variable

I want to instert Category:XXXXX into the 2. line something like this should work, but I have somewhere the wrong sytanx. something with the linebreak goes wrong: sed "2i\\${n}Category:$cat\n" Sample: Titel Blahh Blahh abllk sdhsd sjdhf Blahh Blah Blahh Blahh Should look like... (2 Replies)
Discussion started by: lowmaster
2 Replies

4. Shell Programming and Scripting

How to define a variable with variable definition is stored in a variable?

Hi all, I have a variable say var1 (output from somewhere, which I can't change)which store something like this: echo $var1 name=fred age=25 address="123 abc" password=pass1234 how can I make the variable $name, $age, $address and $password contain the info? I mean do this in a... (1 Reply)
Discussion started by: freddy1228
1 Replies

5. Shell Programming and Scripting

Split variable length and variable format CSV file

Dear all, I have basic knowledge of Unix script and her I am trying to process variable length and variable format CSV file. The file length will depend on the numbers of Earnings/Deductions/Direct Deposits. And The format will depend on whether it is Earnings/Deductions or Direct Deposits... (2 Replies)
Discussion started by: chechun
2 Replies

6. Shell Programming and Scripting

Not able to store command inside a shell variable, and run the variable

Hi, I am trying to do the following thing var='date' $var Above command substitutes date for and in turn runs the date command and i am getting the todays date value. I am trying to do the same thing as following, but facing some problems, unique_host_pro="sed -e ' /#/d'... (3 Replies)
Discussion started by: gvinayagam
3 Replies

7. Shell Programming and Scripting

Variable not found error for a variable which is returned from stored procedure

can anyone please help me with this: i have written a shell script and a stored procedure which has one OUT parameter. now i want to use that out parameter as an input to the unix script but i am getting an error as variable not found. below are the unix scripts and stored procedure... ... (4 Replies)
Discussion started by: swap21783
4 Replies

8. Red Hat

How to pass value of pwd as variable in SED to replace variable in a script file

Hi all, Hereby wish to have your advise for below: Main concept is I intend to get current directory of my script file. This script file will be copied to /etc/init.d. A string in this copy will be replaced with current directory value. Below is original script file: ... (6 Replies)
Discussion started by: cielle
6 Replies

9. Shell Programming and Scripting

[Solved] How to increment and add variable length numbers to a variable in a loop?

Hi All, I have a file which has hundred of records with fixed number of fields. In each record there is set of 8 characters which represent the duration of that activity. I want to sum up the duration present in all the records for a report. The problem is the duration changes per record so I... (5 Replies)
Discussion started by: danish0909
5 Replies

10. UNIX for Advanced & Expert Users

Passing variable as input & storing output in other variable

I have a below syntax its working fine... var12=$(ps -ef | grep apache | awk '{print $2,$4}') Im getting expected output as below: printf "%b\n" "${VAR12}" dell 123 dell 456 dell 457 Now I wrote a while loop.. the output of VAR12 should be passed as input parameters to while loop and results... (5 Replies)
Discussion started by: sam@sam
5 Replies
SET SESSION 
AUTHORIZATION(7) SQL Commands SET SESSION AUTHORIZATION(7) NAME
SET SESSION AUTHORIZATION - set the session user identifier and the current user identifier of the current session SYNOPSIS
SET [ SESSION | LOCAL ] SESSION AUTHORIZATION username SET [ SESSION | LOCAL ] SESSION AUTHORIZATION DEFAULT RESET SESSION AUTHORIZATION DESCRIPTION
This command sets the session user identifier and the current user identifier of the current SQL-session context to be username. The user name may be written as either an identifier or a string literal. The session user identifier is valid for the duration of a connection; for example, it is possible to temporarily become an unprivileged user and later switch back to become a superuser. The session user identifier is initially set to be the (possibly authenticated) user name provided by the client. The current user identi- fier is normally equal to the session user identifier, but may change temporarily in the context of ``setuid'' functions and similar mecha- nisms. The current user identifier is relevant for permission checking. The session user identifier may be changed only if the initial session user (the authenticated user) had the superuser privilege. Other- wise, the command is accepted only if it specifies the authenticated user name. The SESSION and LOCAL modifiers act the same as for the regular SET [set(7)] command. The DEFAULT and RESET forms reset the session and current user identifiers to be the originally authenticated user name. These forms are always accepted. EXAMPLES
SELECT SESSION_USER, CURRENT_USER; current_user | session_user --------------+-------------- peter | peter SET SESSION AUTHORIZATION 'paul'; SELECT SESSION_USER, CURRENT_USER; current_user | session_user --------------+-------------- paul | paul COMPATIBILITY
SQL99 SQL99 allows some other expressions to appear in place of the literal username which are not important in practice. PostgreSQL allows iden- tifier syntax ("username"), which SQL does not. SQL does not allow this command during a transaction; PostgreSQL does not make this restriction because there is no reason to. The privileges necessary to execute this command are left implementation-defined by the stan- dard. SQL - Language Statements 2001-04-21 SET SESSION AUTHORIZATION(7)
All times are GMT -4. The time now is 05:08 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy