07-11-2001
Use GNU date and do:
date --date="15 days ago"
or, since the link above seems to be broken, just search the forums for the string "yesterdays date".
Last edited by PxT; 02-15-2002 at 09:56 AM..
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hi,
I am trying to modify a script which accepts date in format dd/mm/yy. I am trying to modify the script so that it retrieves the date that was 15 days earlier from today as start date. Eg.if today is 05/09/2006, the script should retrieve 21/08/2006 as start date. Is there any script/code to... (2 Replies)
Discussion started by: ritzwan0
2 Replies
2. Shell Programming and Scripting
Reuirement:
I have a set of files ina diectory which has the name in format "WWW-YYYYmmDD"
like, WWW-20070226. for 26th FEB 2007.
Now I need to write a shell script which should move the files to directory named "old" in the same directory if date attached to file is 90 days prior to today's... (1 Reply)
Discussion started by: jnanesh.b
1 Replies
3. Shell Programming and Scripting
I need to increment a date value through shell script.
Input value consist of start date and end date in DATE format of unix.
For eg.
I need increment a date value of 1/1/09 to 31/12/09 i.e for a whole yr.
The output must look like
1/1/09
2/2/09
.
.
.
31/1/09
.
.
1/2/09
.
28/2/09... (1 Reply)
Discussion started by: sunil087
1 Replies
4. UNIX for Dummies Questions & Answers
Hello,
I am trying to show today's date and time in a better format than ‘date' (Using positional parameters). I found a command mktime and am wondering if this is the best command to use or will this also show me the time elapse since 1/30/70? Any help would be greatly appreciated, Thanks... (3 Replies)
Discussion started by: citizencro
3 Replies
5. Shell Programming and Scripting
Hi,
I want to compare today's date(DDMMYYYY) with yesterday(DDMMYYYY) from system date,if (today month = yesterday month) then execute alter query else do nothing.
The above requirement i want in Shell script(KSH)...
Can any one please help me?
Double post, continued here. (0 Replies)
Discussion started by: kumarmsk1331
0 Replies
6. UNIX for Dummies Questions & Answers
hi friends,
I m trying to write a script which compares to dates.
for this i am converting dates into no using synatx
as below
v2=`date | awk '{print $2,$3,$4}'`
v3=`date +%s -d "$v2"`
this syntax is working in bash shell ,but fails in ksh shell.
please suggest on this. (12 Replies)
Discussion started by: Jcpratap
12 Replies
7. UNIX for Dummies Questions & Answers
Hi ,
How would i write a shell script to run the code from one date to another date EXample 2014-01-01 to 2014-02-28, can i any provide some clue on this (4 Replies)
Discussion started by: vikatakavi
4 Replies
8. Shell Programming and Scripting
hi all,
How to compare two files whether they are same are not...? like i had my input files as 20141201_file.txt and 20141130_file2.txt
how to compare the above files based on date .. like todays file and yesterdays file...? (4 Replies)
Discussion started by: hemanthsaikumar
4 Replies
9. Linux
Hi,
My question is how to calculate the quarter end date according to the current date in shell script? (2 Replies)
Discussion started by: Divya_1234
2 Replies
10. UNIX for Beginners Questions & Answers
Hi Community!
Following on from this code in another thread:
#!/bin/bash
file_string=`/bin/cat date.txt | /usr/bin/awk '{print $5,$4,$7,$6,$8}'`
file_date=`/bin/date -d "$file_string"`
file_epoch=`/bin/date -d "$file_string" +%s`
now_epoch=`/bin/date +%s`
if
then
#let... (2 Replies)
Discussion started by: Greenage
2 Replies
LEARN ABOUT DEBIAN
arbitron
ARBITRON(8) System Manager's Manual ARBITRON(8)
*
NAME
arbitron - arbitron mailboxes
SYNOPSIS
arbitron [ -C config-file ] [ -o ] [ -u ] [ -l ] [ -p months ]
[ -d days | -D mmddyyyy[:mmddyyyy] ] mailbox...
DESCRIPTION
Arbitron collects and reports readership statistics for mailboxes on the server. It also optionally prunes the mailboxes of Seen state
for dormant users.
Arbitron produces one line of output per mailbox, reporting the mailbox name followed by a space, followed by the number of readers (and if
-u is specified, followed by a colon and a comma-separated list of the readers userids), and if -o is not specified, another space and the
number of subscribers (and if -u is specified, followed by a colon and a comma-separated list of the subscribers userids). IMPORTANT: This
format is subject to change in future versions.
Each "reader" is a distinct authentication identity which has "s" rights to the mailbox and which has SELECTed the mailbox within either
the past days days or the specified date range. Users are not counted as reading their own personal mailboxes. Personal mailboxes are not
reported unless there is at least one reader other than the mailboxes owner.
Arbitron reads its configuration options out of the imapd.conf(5) file unless specified otherwise by -C.
OPTIONS
-C config-file
Read configuration options from config-file.
-o "old way" -- do not report subscribers.
-u Report userids in addition to the count(s).
-l Enable long reporting (comma delimited table consisting of mbox, userid, r/s, start time, end time).
-d days
Count as a reader an authentication identity which has SELECTed the mailbox within days days. Default is 30.
-D mmddyyyy[:mmddyyyy]
Count as a reader an authentication identity which has SELECTed the mailbox within the given date range. The start date and
optional end date are specified as 2-digit month of the year, 2-digit day of the month, and 4-digit year. If the end date is not
specified, then the current system time is used as the end time.
-p months
Prune Seen state for users who have not SELECTed the mailbox within months months. Default is infinity.
FILES
/etc/imapd.conf
CMU
Project Cyrus ARBITRON(8)