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Full Discussion: Progress reporting
Top Forums UNIX for Dummies Questions & Answers Progress reporting Post 36370 by google on Wednesday 28th of May 2003 08:12:48 AM
Old 05-28-2003
Quote:
if test -f /u/ttc/
then #File or directory exists so ask for confirmation

echo -n "Ready to begin copy, continue? [y/n]"; read choice
if [ "$choice" -eq y ] || [ "$choice" -eq Y]; then echo "Copying files"
cp -r $livecomp $copycomp
mv -r $livecomp $tempcomp
if [ test -f /u/ttc/ ]
then
echo "Ready to begin copy, continue? [y/n]" ; read choice

if [ "$choice" -eq y ] || [ "$choice" -eq Y]
then
DIR_COUNT=`wc -l /u/ttc/`
TOTAL=$DIR_COUNT
echo "Directory Count is ${DIR_COUNT}. Begining Copy"

while [ $DIR_COUNT -gt 0 ]
do
echo " Copying file $DIR_COUNT of $TOTAL"
cp -r $livecomp $copycomp
mv -r $livecomp $tempcomp
let DIR_COUNT=$DIR_COUNT-1
done

Check syntax as I just quickly typed this out..there are better ways to do this, this is just to give you an idea of how to go about implementing your fix. You may also want to invest in some error checking following the copy command (unless of course you are running as root). Also, you may want to change the -eq to = since you are comparing a string an not an integer. Another point would be to log the events in your script (which Im sure you are doing Smilie )

Last edited by google; 05-28-2003 at 09:30 AM..
 

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ECHO(3) 								 1								   ECHO(3)

echo - Output one or more strings

SYNOPSIS
void echo (string $arg1, [string $...]) DESCRIPTION
Outputs all parameters. echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. echo (unlike some other language constructs) does not behave like a function, so it cannot always be used in the context of a function. Additionally, if you want to pass more than one parameter to echo, the parameters must not be enclosed within parentheses. echo also has a shortcut syntax, where you can immediately follow the opening tag with an equals sign. Prior to PHP 5.4.0, this short syn- tax only works with the short_open_tag configuration setting enabled. I have <?=$foo?> foo. PARAMETERS
o $arg1 - The parameter to output. o $... - RETURN VALUES
No value is returned. EXAMPLES
Example #1 echo examples <?php echo "Hello World"; echo "This spans multiple lines. The newlines will be output as well"; echo "This spans multiple lines. The newlines will be output as well."; echo "Escaping characters is done "Like this"."; // You can use variables inside of an echo statement $foo = "foobar"; $bar = "barbaz"; echo "foo is $foo"; // foo is foobar // You can also use arrays $baz = array("value" => "foo"); echo "this is {$baz['value']} !"; // this is foo ! // Using single quotes will print the variable name, not the value echo 'foo is $foo'; // foo is $foo // If you are not using any other characters, you can just echo variables echo $foo; // foobar echo $foo,$bar; // foobarbarbaz // Some people prefer passing multiple parameters to echo over concatenation. echo 'This ', 'string ', 'was ', 'made ', 'with multiple parameters.', chr(10); echo 'This ' . 'string ' . 'was ' . 'made ' . 'with concatenation.' . " "; echo <<<END This uses the "here document" syntax to output multiple lines with $variable interpolation. Note that the here document terminator must appear on a line with just a semicolon. no extra whitespace! END; // Because echo does not behave like a function, the following code is invalid. ($some_var) ? echo 'true' : echo 'false'; // However, the following examples will work: ($some_var) ? print 'true' : print 'false'; // print is also a construct, but // it behaves like a function, so // it may be used in this context. echo $some_var ? 'true': 'false'; // changing the statement around ?> NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. SEE ALSO
print(3), printf(3), flush(3), Heredoc syntax. PHP Documentation Group ECHO(3)
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