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Full Discussion: Julian Date
Top Forums Shell Programming and Scripting Julian Date Post 35562 by oombera on Thursday 17th of April 2003 02:41:38 PM
Old 04-17-2003
Well if you can alter the script that's passing the parameter, you could change the piece of code, such as date +%Y%j, so that it sends what you want it to send, such as date +%Y%m%d.

Otherwise...
Assuming the variable that stores that passed value is called varPassed, you can put this (ksh) code in a file called someScript, make it executable, and call it with newValue=`someScript $varPassed`:

Code:
varPassed=$1

month=1
flag=0

theYear=`echo $varPassed | awk '{print substr ($0, 1, 4)'}`
dayOfYear=`echo $varPassed | awk '{print substr ($0, 5, 3)'}`
dayOfYear=`expr $dayOfYear - 0`

TestLeapYear() {
  if [[ `expr $theYear % 4` != 0 && $dayOfYear -gt 28 ]] then
    month=`expr $month + 1`
    dayOfYear=`expr $dayOfYear - 28`
  else
    if [[ `expr $theYear % 4` = 0 && $dayOfYear -gt 29 ]] then
      month=`expr $month + 1`
      dayOfYear=`expr $dayOfYear - 29`
    else
      flag=1
    fi
  fi
}

Days30() {
  if [[ $dayOfYear -gt 30 ]] then
    month=`expr $month + 1`
    dayOfYear=`expr $dayOfYear - 30`
  else
    flag=1
  fi
}

Days31() {
  if [[ $dayOfYear -gt 31 ]] then
    month=`expr $month + 1`
    dayOfYear=`expr $dayOfYear - 31`
  else
    flag=1
  fi
}

Days31 #january
if [[ $flag = 0 ]] then
  TestLeapYear #february
fi
if [[ $flag = 0 ]] then
  Days31 #march
fi
if [[ $flag = 0 ]] then
  Days30 #april
fi
if [[ $flag = 0 ]] then
  Days31 #may
fi
if [[ $flag = 0 ]] then
  Days30 #june
fi
if [[ $flag = 0 ]] then
  Days31 #july
fi
if [[ $flag = 0 ]] then
  Days31 #august
fi
if [[ $flag = 0 ]] then
  Days30 #september
fi
if [[ $flag = 0 ]] then
  Days31 #october
fi
if [[ $flag = 0 ]] then
  Days30 #november
fi

if [[ $month -lt 10 ]] then
  month=0$month
fi
if [[ $dayOfYear -lt 10 ]] then
  dayOfYear=0$dayOfYear
fi

echo $theYear$month$dayOfYear


Last edited by oombera; 04-17-2003 at 03:52 PM..
This User Gave Thanks to oombera For This Post:
 

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CAL_FROM_JD(3)								 1							    CAL_FROM_JD(3)

cal_from_jd - Converts from Julian Day Count to a supported calendar

SYNOPSIS
array cal_from_jd (int $jd, int $calendar) DESCRIPTION
cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH and CAL_FRENCH. PARAMETERS
o $jd - Julian day as integer o $calendar - Calendar to convert to RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and the date in string form "month/day/year". EXAMPLES
Example #1 cal_from_jd(3) example <?php $today = unixtojd(mktime(0, 0, 0, 8, 16, 2003)); print_r(cal_from_jd($today, CAL_GREGORIAN)); ?> The above example will output: Array ( [date] => 8/16/2003 [month] => 8 [day] => 16 [year] => 2003 [dow] => 6 [abbrevdayname] => Sat [dayname] => Saturday [abbrevmonth] => Aug [monthname] => August ) SEE ALSO
cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3). PHP Documentation Group CAL_FROM_JD(3)
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