hey guys..
probably a simple question but i cant seem to find any info on it.
i have a small array of strings, and i want to concatenate the contents of the array into one big string.
any ideas on how i can do this?
cheers. (2 Replies)
Hi, I'm quite new at unix and was wondering if anyone could help me with this.
I have 2 arrays:
eg. STAT=online, STAT=offline, STAT=online
WWN=xxxx1, WWN=xxxx2, WWN=xxxx3
I got these information from a script using fcinfo hba-port that runs through a loop.
Now, I want to store... (2 Replies)
HI
I need to concatenate two files which are having headers. the result file should contain only the header from first file only and the header in second file have to be skipped.
file1:
name age
sriram 23
file2
name age
prabu 25
result file should be
name age
sriram 23
prabu ... (6 Replies)
Hi all,
I'm trying to do a very simple script, as you can see as follow:
#!/bin/bash
#Valorizzazione Token presenti nel file di properties
var_path_weblogic="`cat weblogic.properties | grep "dir_wl" | /usr/xpg4/bin/awk '{print $3}'`"
var_ip_address="`cat... (5 Replies)
Hi All ,
i`m writing a script , i stucked in middle .
Script
echo "Please Enter the INSTANCE name"
read iName
echo "The INSTANCE name is $iName"
more /opt/IBMIHS*/conf/httpd.conf_"$iName"
script end
here i`m getting error as :
Error
/opt/IBMIHS*/conf/httpd.conf_w101:... (7 Replies)
Hi
This is a simple one but I got a lost in translation when doing.
What I want to do, given both variables in the example below, to get one value at the time from both variables, for example:
1:a
2:b
etc...
I need to get this in bash scripting
code:
varas="1 2 3 4"
varbs="a b c d"... (4 Replies)
Hi folks,
I am facing problem when I concat variables with the string.
Value for 'JDBC_CLASSES' variable looks malformed (/classes12.zip2.0KAGES)
But, my expected result for 'JDBC_CLASSES' is
/opt/API-R111/PACKAGES/jdbc/ORACLE9.2.0/classes12.zip
Am I missing anything here?
My... (10 Replies)
Hi,
I have file called "3rdparty.dat"
I want to concatenate current YYYYMMDD to it. Snd result should be like 3rdParty20111110.dat.
How can i do this?
Thanks in advance. (3 Replies)
Hello all
The following line :
df -h | awk '{print $5}'| head -2 |tail -1
gives me an output of '2.2G'
How can I remove the 'G' so that I can use the 2.2 for further calculations ? (8 Replies)
Hi All,
I am having a situation where am capturing results in two variables from an xml file. However, I am looking to print those two variables with pipe in between them and these variable are multi-line.
This is how my 1st variable looks like:
20181225010
20190224010
20190224010... (8 Replies)
Discussion started by: svks1985
8 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)