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Full Discussion: awk with (if condition)
Top Forums UNIX for Beginners Questions & Answers awk with (if condition) Post 303046328 by RudiC on Friday 1st of May 2020 12:56:31 AM
Old 05-01-2020
Quote:
Originally Posted by sea
And that is why I dont understand why $1 == Name removes the "Name" line and shows the remaining values...
It doesn't. It would remove any line with an emtpy $1, of which there is none. You can leave it out entirely. The $4 < 7000 removes the header line. $4 > 7000 would not; we'd need a different criterion, then.



Quote:
And the TO did/does not want the header-line shown, that is why I settled for $1 ==! "Name"
Hmm - that ==! is a construct that I can't get my head around. It obviously is a correct syntax - no complaints by the interpreter. So the == must be separated from the ! which then logically negates the NAME variable's contents and results in a 1 or 0 which in turn is tried to be matched against $1. And, so it is. Add a line starting with a 0 or 1 and see what's going to happen.
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Moose::Cookbook::Roles::ApplicationToInstance(3pm)	User Contributed Perl Documentation	Moose::Cookbook::Roles::ApplicationToInstance(3pm)

NAME
Moose::Cookbook::Roles::ApplicationToInstance - Applying a role to an object instance VERSION
version 2.0603 SYNOPSIS
package MyApp::Role::Job::Manager; use List::Util qw( first ); use Moose::Role; has 'employees' => ( is => 'rw', isa => 'ArrayRef[Employee]', ); sub assign_work { my $self = shift; my $work = shift; my $employee = first { !$_->has_work } @{ $self->employees }; die 'All my employees have work to do!' unless $employee; $employee->work($work); } package main; my $lisa = Employee->new( name => 'Lisa' ); MyApp::Role::Job::Manager->meta->apply($lisa); my $homer = Employee->new( name => 'Homer' ); my $bart = Employee->new( name => 'Bart' ); my $marge = Employee->new( name => 'Marge' ); $lisa->employees( [ $homer, $bart, $marge ] ); $lisa->assign_work('mow the lawn'); DESCRIPTION
In this recipe, we show how a role can be applied to an object. In this specific case, we are giving an employee managerial responsibilities. Applying a role to an object is simple. The Moose::Meta::Role object provides an "apply" method. This method will do the right thing when given an object instance. MyApp::Role::Job::Manager->meta->apply($lisa); We could also use the "apply_all_roles" function from Moose::Util. apply_all_roles( $person, MyApp::Role::Job::Manager->meta ); The main advantage of using "apply_all_roles" is that it can be used to apply more than one role at a time. We could also pass parameters to the role we're applying: MyApp::Role::Job::Manager->meta->apply( $lisa, -alias => { assign_work => 'get_off_your_lazy_behind' }, ); We saw examples of how method exclusion and alias working in Moose::Cookbook::Roles::Restartable_AdvancedComposition. CONCLUSION
Applying a role to an object instance is a useful tool for adding behavior to existing objects. In our example, it is effective used to model a promotion. It can also be useful as a sort of controlled monkey-patching for existing code, particularly non-Moose code. For example, you could create a debugging role and apply it to an object at runtime. AUTHOR
Moose is maintained by the Moose Cabal, along with the help of many contributors. See "CABAL" in Moose and "CONTRIBUTORS" in Moose for details. COPYRIGHT AND LICENSE
This software is copyright (c) 2012 by Infinity Interactive, Inc.. This is free software; you can redistribute it and/or modify it under the same terms as the Perl 5 programming language system itself. perl v5.14.2 2012-06-28 Moose::Cookbook::Roles::ApplicationToInstance(3pm)
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