| Hi have two directory with below name in “/opt“

1-Source
2-Destination 

In “Source” directory there is a lot’s of files, with extensions (doc, docx , ppt, xls,...).
In “Destination” directory only pdf version of (doc, docx) files that exist in source stored.

Now I want to create script that use “diff” command check “source” and get list of only (doc, docx) files after that look for related pdf file in “Destination” if pdf version of (doc, docx) not exist in “destination” store list of them on a file.

E.g.

1-Source
[CODE]File1.doc
File2.docx
File3.doc
File4.ppt
File5.xls
File6.doc[/CODE]

2-Destination 
[CODE]File1.pdf
File3.pdf
[/CODE]

Expected result after run script is:
[CODE]File2.docx
File6.doc[/CODE]

Here is my script
[CODE]diff -r “/opt/source” “/opt/destination“[/CODE]


Any recommendation?
Thanks



UPDATE 
Follow below post and work like charm:

[CODE]comm -23 <(find dir1 -type f -exec bash -c 'basename "${0%.*}"' {} \; | sort) <(find dir2 -type f -exec bash -c 'basename "${0%.*}"' {} \; | sort)
test1[/CODE]

[url=https://unix.stackexchange.com/questions/178321/diff-two-directories-but-ignore-the-extensions]filenames - diff two directories, but ignore the extensions - Unix & Linux Stack Exchange[/url]

https://www.unix.com/unix-for-beginners-questions-and-answers/284088-compare-two-directory-find-differents.html

https://community.unix.com/t/compare-two-directory-and-find-differents/377962