Hello,
I have 800 or so files with 3 columns each and >10000 lines each.
For each file and each line I would like to print the maximum column number for each line. Then I would like to 'paste' each of these files together (column-wise) so that the file with expression in label '_1' is the... (6 Replies)
Hi All,
I am performing addition of two inetger variables which assigning output to a new variable getting following error.
Check1.sh
#!/bin/ksh
filesrc=/usr/kk/Source1.txt
filetgt=/usr/kk/Source2.txt
FINAL_COUNTS= `awk '{n++} END {printf "%012d\n",n}' ${filesrc} ${filetgt}`... (3 Replies)
Hi All,
I want to pass few dynamic arguments to shell script. The number of arguments differ each time I call the script.
I want to print the arguments using the for loop as below. But not working out.
for (( i=1; i<=$#; i++ ))
do
echo $"($i)"
done
/bin/sh test.sh arg1 arg2 arg3
... (1 Reply)
Hi ,
i want to print the output in line by line
while read LINE
do
echo $LINE | grep UCM | egrep '(Shutdown|Unavailable)'
echo $LINE | grep SRBr | egrep '(Shutdown|Unavailable)'
echo $LINE | grep SRP| egrep '(Shutdown|Unavailable)'
echo $LINE | grep OM | grep JMS|... (7 Replies)
Hi,
I am trying to print copy percentage completion dynamically by using the script below,
#!/bin/bash
dest_size=0
orig_size=`du -sk $sourcefile | awk '{print $1}'`
while ; do
dest_size=`du -sk $destfile | awk '{print $1}'`
coyp_percentage=`echo "scale=2; $dest_size*100/$orig_size"... (4 Replies)
In the bash below I am trying to loop through all the R1.gz in a directory (always 1), store them in ARRAY, and cut them before the second _. That is being done but I can't seem to print then one a single line seperated by a space. Is the below the best way or is there a better solution? Thank you... (3 Replies)
I am unable to loop print a python string array in my unix shell script:
~/readarr.sh '{{ myarr }}'
more readarr.sh
echo "Parameter 1:"$1
MYARRAY= $1
IFS=
MYARRAY=`python <<< "print ' '.join($MYARRAY)"`
for a in "$MYARRAY"; do
echo "Printing Array: $a"
done
Can you... (10 Replies)
Currently using below script but echo it print the output in two line.
Input file all-vm-final-2.txt
CEALA08893 SDDC_SCUN DS_SIO_Workload_SAPUI_UAT_01 4
CEALA09546 SDDC_SCUN DS-SIO-PD5_Workload_UAT_SP1_Flash_07 4
CEALA09702 SDDC_SCUN DS-VSAN-RMP-WORKLOAD01 4
DEALA08762 SDDC_LDC... (3 Replies)
Discussion started by: ranjancom2000
3 Replies
LEARN ABOUT DEBIAN
stat::lsmode
lsMode(3pm) User Contributed Perl Documentation lsMode(3pm)NAME
Stat::lsMode - format file modes like the "ls -l" command does
SYNOPSIS
use Stat::lsMode;
$mode = (stat $file)[2];
$permissions = format_mode($mode);
# $permissions is now something like `drwxr-xr-x'
$permissions = file_mode($file); # Same as above
$permissions = format_perms(0644); # Produces just 'rw-r--r--'
$permissions = format_perms(644); # This generates a warning message:
# mode 644 is very surprising. Perhaps you meant 0644...
Stat::lsMode->novice(0); # Disable warning messages
DESCRIPTION
"Stat::lsMode" generates mode and permission strings that look like the ones generated by the Unix "ls -l" command. For example, a regular
file that is readable by everyone and writable only by its owner has the mode string "-rw-r--r--". "Stat::lsMode" will either examine the
file and produce the right mode string for you, or you can pass it the mode that you get back from Perl's "stat" call.
"format_mode"
Given a mode number (such as the third element of the list returned by "stat"), return the appopriate ten-character mode string as it would
have been generated by "ls -l". For example, consider a directory that is readable and searchable by everyone, and also writable by its
owner. Such a directory will have mode 040755. When passed this value, "format_mode" will return the string "drwxr-xr-x".
If "format_mode" is passed a permission number like 0755, it will return a nine-character string insted, with no leading character to say
what the file type is. For example, "format_mode(0755)" will return just "rwxr-xr-x", without the leading "d".
"file_mode"
Given a filename, do "lstat" on the file to determine the mode, and return the mode, formatted as above.
Novice Operation Mode
A common mistake when dealing with permission modes is to use 644 where you meant to use 0644. Every permission has a numeric
representation, but the representation only makes sense when you write the number in octal. The decimal number 644 corresponds to a
permission setting, but not the one you think. If you write it in octal you get 01204, which corresponds to the unlikely permissions
"-w----r-T", not to "rw-r--r--".
The appearance of the bizarre permission "-w----r-T" in a program is almost a sure sign that someone used 644 when they meant to use 0644.
By default, this module will detect the use of such unlikely permissions and issue a warning if you try to format them. To disable these
warnings, use
Stat::lsMode->novice(0); # disable novice mode
Stat::lsMode->novice(1); # enable novice mode again
The surprising permissions that are diagnosed by this mode are:
111 => --xr-xrwx
400 => rw--w----
440 => rw-rwx---
444 => rw-rwxr--
551 => ---r--rwt
600 => --x-wx--T
640 => -w------T
644 => -w----r-T
660 => -w--w-r-T
664 => -w--wx--T
666 => -w--wx-wT
700 => -w-rwxr-T
711 => -wx---rwt
750 => -wxr-xrwT
751 => -wxr-xrwt
751 => -wxr-xrwt
755 => -wxrw--wt
770 => r------wT
771 => r------wt
775 => r-----rwt
777 => r----x--t
Of these, only 400 is remotely plausible.
BUGS
As far as I know, the precise definition of the mode bits is portable between varieties of Unix. The module should, however, examine
"stat.h" or use some other method to find out if there are any local variations, because Unix being Unix, someone somewhere probably does
it differently.
Maybe it "file_mode" should have an option that says that if the file is a symlink, to format the mode of the pointed to file instead of
the mode of the link itself, the way "ls -Ll" does.
SEE ALSO
o "http://www.plover.com/~mjd/perl/lsMode/".
o ls
o chmod
o stat
AUTHOR
Mark-Jason Dominus ("mjd-perl-lsmode@plover.com").
perl v5.10.1 1998-04-20 lsMode(3pm)