I am having a floating variable which may or may not be float, but the output must be in interger only.
Suppose the variable "a" has float value, then it should be convert to nearest interger value. For example : 23.4 should be convert to 23 and 27.86 should be convert to 28.
So i tried th below code and and the error.
I'm using ksh. Could you please help me on this?
i want to convert from an integer to a string..in unix...i am writing a C program with embedded SQL...
I remeber using itoa...but for some reason it doesnt work......i cant find it in the manual.....
Maybe that is the wrong command.....
but i have checked Dev Studio.....and it doest exist in the... (6 Replies)
Hi,
I am trying to write a script to extract multiple sets of data from a chemistry output file. The problem section is in the following format...
Geometry "geometry" -> "geometry"
1 Pd 46.0000 -0.19290971 0.00535260 0.02297606
2 P ... (7 Replies)
Hiii
I actually intent to check the integer or floating point number input by user i.e. 23, 100, 55.25, 12.50 ..etc. However, when someone input strings or alpha character, my program has to show invalid input.!! Is there any Unix shell script syntax can help me to check ?
Thanking you (2 Replies)
Hi !
I'm looking for a way to transform certain floating point numbers in a one-line, variable length file to integers.
I can do this in a crude way with sed :
sed -e 's/0\.\(\):/\1:/g' -e 's/0\.0\(\):/\1:/g' -e 's/1\.000:/100:/g' myfile ... but this doesn't handle the rounding correctly.
... (3 Replies)
Hi !
How to increment a varibale in ksh.
#!/bin/ksh
set -x
RELEASE_NUM=5.2.103
VAL=0.0.1
RELEASE_NUM=`echo $RELEASE_NUM + $VAL | bc`
echo $RELEASE_NUM
The above code is throwing this error.
+ RELEASE_NUM=5.2.103 (2 Replies)
Hi fellows!!
i'm doing something which is not working out for me properly which i don't understand why
nowdate=`date +%s`
echo $nowdate
now the problem how to convert a date which is stored in a variable
mydate="22/Oct/2011"
mydate=`date -d '$mydate' +%s`
it gives error... (11 Replies)
I am running some commands and I am trying to get an output into a variable. I am having problem when I try to put that value in while loop, it says integer value expected. What's the best way to accomplish this
remaining=$(symclone -sid XXX -f Clone_test query | grep MB | awk '{print... (1 Reply)
Using below command
awk 'NR==FNR{A=$1;next}
{sum+=($2*A)}END{OFMT="%20f";print int(sum)}' Market.txt Product.txt
answer:351770174.00000
how to convert this to 351770174.
when i try with below command i am getting different result.
awk 'NR==FNR{A=$1;next}... (3 Replies)
I have a document that has 7 columns.
eg.
$1 $2 $3 $4 $5 $6 $7
string string string string integer integer integer
The 6th and 7th columns are a mix of integers and floating decimals (with 4 decimal places). I need to convert the last 2 columns so that all... (3 Replies)
Hello Guys,
I have a floating point number 1.14475E+15 I want to convert this number in to full number (Integer or Big integer). I tried couple of functions it did not work. When I use INT=${FLOAT/.*} I am getting value as 1. I don't want a truncated value
#!/bin/bash
#... (9 Replies)
Discussion started by: skatpally
9 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)