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Top Forums UNIX for Beginners Questions & Answers Unable to execute the comand on the remote Linux hosts Post 303046020 by JackKerrnal on Tuesday 21st of April 2020 06:44:11 PM
Old 04-21-2020
Unable to execute the comand on the remote Linux hosts

I have multiple hosts ( More than 20) and need to execute the command but it is not working as expected.


1. This snippet of the code runs on multiple hosts and gives me the process id on the host where i am running .

Code:
      for hsts in `cat /a/b/c//hsts.txt`  # hsts.txt file contains all the hosts
         do
         ssh ${id}@${hsts} "cat /z/y/x|tail -1" | awk '{print $30}'
        done

2. I need to modify the above command where i need to see the process which is running based on the process id which i am getting from above snippet of the code.


The below snippet runs on individual hosts and it is displaying me the process but if i incorporate the above in the for loop it is not working . Appreciate your help

on this.
Code:
   ps -ef |grep `cat /z/y/x|tail -1 |awk '{print $30}'`

Moderator's Comments:
Mod Comment
Please use code tags to improve readability and follow the forum rules.

Last edited by Peasant; 04-22-2020 at 01:12 AM..
 

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UNBUFFER(1)						      General Commands Manual						       UNBUFFER(1)

NAME
unbuffer - unbuffer output SYNOPSIS
unbuffer program [ args ] INTRODUCTION
unbuffer disables the output buffering that occurs when program output is redirected from non-interactive programs. For example, suppose you are watching the output from a fifo by running it through od and then more. od -c /tmp/fifo | more You will not see anything until a full page of output has been produced. You can disable this automatic buffering as follows: unbuffer od -c /tmp/fifo | more Normally, unbuffer does not read from stdin. This simplifies use of unbuffer in some situations. To use unbuffer in a pipeline, use the -p flag. Example: process1 | unbuffer -p process2 | process3 CAVEATS
unbuffer -p may appear to work incorrectly if a process feeding input to unbuffer exits. Consider: process1 | unbuffer -p process2 | process3 If process1 exits, process2 may not yet have finished. It is impossible for unbuffer to know long to wait for process2 and process2 may not ever finish, for example, if it is a filter. For expediency, unbuffer simply exits when it encounters an EOF from either its input or process2. In order to have a version of unbuffer that worked in all situations, an oracle would be necessary. If you want an application-specific solution, workarounds or hand-coded Expect may be more suitable. For example, the following example shows how to allow grep to finish pro- cessing when the cat before it finishes first. Using cat to feed grep would never require unbuffer in real life. It is merely a place- holder for some imaginary process that may or may not finish. Similarly, the final cat at the end of the pipeline is also a placeholder for another process. $ cat /tmp/abcdef.log | grep abc | cat abcdef xxxabc defxxx $ cat /tmp/abcdef.log | unbuffer grep abc | cat $ (cat /tmp/abcdef.log ; sleep 1) | unbuffer grep abc | cat abcdef xxxabc defxxx $ BUGS
The man page is longer than the program. SEE ALSO
"Exploring Expect: A Tcl-Based Toolkit for Automating Interactive Programs" by Don Libes, O'Reilly and Associates, January 1995. AUTHOR
Don Libes, National Institute of Standards and Technology 1 June 1994 UNBUFFER(1)
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